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HashPractice Paper Karla T. #49

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40 changes: 32 additions & 8 deletions hash_practice/exercises.py
Original file line number Diff line number Diff line change
Expand Up @@ -2,19 +2,43 @@
def grouped_anagrams(strings):
""" This method will return an array of arrays.
Each subarray will have strings which are anagrams of each other
Time Complexity: ?
Space Complexity: ?
Time Complexity: O(n)
Space Complexity: O(1)
"""
Comment on lines 2 to 7

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👍 However space complexity is O(n) since you're building a dictionary of all the words.

pass

dict = {}
for string in strings:
sorted_string = ''.join(sorted(string))
if sorted_string in dict:
dict[sorted_string].append(string)
else:
dict[sorted_string] = [string]
return_list = []
for key, value in dict.items():
return_list.append(value)
return return_list


def top_k_frequent_elements(nums, k):
""" This method will return the k most common elements
In the case of a tie it will select the first occuring element.
Time Complexity: ?
Space Complexity: ?
Time Complexity: O(n log n)
Space Complexity: O(n)
"""
Comment on lines 22 to 27

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👍 I would also say that the time complexity is O(nk) since you have the nested loop in lines 37 - 40 (max has to loop through the list).

pass

frequency_dict = {}
if nums == []:
return nums
for num in nums:
if num in frequency_dict:
frequency_dict[num] += 1
else:
frequency_dict[num] = 1
return_list = []
for i in range(k):
highest_value = max(frequency_dict, key = frequency_dict.get)
return_list.append(highest_value)
frequency_dict.pop(highest_value)
return return_list

def valid_sudoku(table):
""" This method will return the true if the table is still
Expand All @@ -25,5 +49,5 @@ def valid_sudoku(table):
Time Complexity: ?
Space Complexity: ?
"""
pass