[highball] week4 solutions

longest-consecutive-sequence/highball.js

@@ -0,0 +1,32 @@
+//time-complexity : O(n)
+//space-complexity : O(n)
+
+const longestConsecutive = function (nums) {
+  let longest = 0;
+  const set = new Set(nums);
+
+  while (set.size > 0) {
+    let count = 0;
+    const originalSeed = set.values().next().value; //set의 첫 번째 원소 get
+
+    seed = originalSeed;
+
+    while (set.has(seed)) {
+      set.delete(seed);
+      count++;
+      seed += 1;
+    }
+
+    seed = originalSeed - 1;
+
+    while (set.has(seed)) {
+      set.delete(seed);
+      count++;
+      seed -= 1;
+    }
+
+    if (count > longest) longest = count;
+  }
+
+  return longest;
+};

maximum-product-subarray/highball.js

@@ -0,0 +1,84 @@
+//time-complexity : O(n)
+//space-complexity : O(n)
+
+const maxProduct = function (nums) {
+  let subarrays = [];
+  let subarray = [];
+  let zeroCount = 0;
+
+  /* -------------------------------------------------------------------------- */
+  /*                     nonzero subarray 잘라서 subarrays에 넣기                  */
+  /* -------------------------------------------------------------------------- */
+  for (let i = 0; i < nums.length; i++) {
+    if (nums[i] === 0) {
+      if (subarray.length > 0) {
+        subarrays.push([...subarray]);
+        subarray.length = 0; //각 element의 metadata를 garbage collection에 들어가야 하는 것으로 marking할 뿐이므로 O(1)!
+      }
+      zeroCount++;
+      continue;
+    }
+    subarray.push(nums[i]);
+  }
+  if (subarray.length > 0) {
+    subarrays.push([...subarray]);
+  }
+
+  /* -------------------------------------------------------------------------- */
+  /*                   각 subarray의 maxProduct들 중 최대값 리턴하기                  */
+  /* -------------------------------------------------------------------------- */
+  if (zeroCount === 0) {
+    return maxProductNonzero(nums);
+  } else {
+    let max = 0;
+    for (let i = 0; i < subarrays.length; i++) {
+      max = Math.max(maxProductNonzero(subarrays[i]), max);
+    }
+    return max;
+  }
+};
+
+const maxProductNonzero = function (nonZeroNums) {
+  if (nonZeroNums.length === 1) return nonZeroNums[0]; //firstNegativeIndex = lastNegativeIndex = 0이 되어 버려서 frontProduct와 backProduct 중 어느 것도 계산이 안 돼버리므로 early return으로 처리.
+
+  let firstNegativeIndex = -1;
+  let lastNegativeIndex = -1;
+  let negativeCount = 0;
+  for (let i = 0; i < nonZeroNums.length; i++) {
+    if (nonZeroNums[i] < 0 && firstNegativeIndex !== lastNegativeIndex) {
+      lastNegativeIndex = i;
+      negativeCount++;
+    }
+    if (nonZeroNums[i] < 0 && firstNegativeIndex === lastNegativeIndex) {
+      firstNegativeIndex = i;
+      negativeCount++;
+    }
+  }
+
+  if (negativeCount === 1) {
+    lastNegativeIndex = firstNegativeIndex;
+  }
+
+  if (negativeCount % 2 === 0) {
+    /* -------------------------------------------------------------------------- */
+    /*                     음수 개수가 짝수 개면 그냥 전체 곱한 게 최대값임                  */
+    /* -------------------------------------------------------------------------- */
+    let product = 1;
+    for (let i = 0; i < nonZeroNums.length; i++) {
+      product *= nonZeroNums[i];
+    }
+    return product;
+  } else {
+    /* -------------------------------------------------------------------------- */
+    /*        음수 개수가 홀수 개면 처음부터 lastNegativeIndex 직전까지 곱한 수 혹은          */
+    /*        firstNegativeIndex부터 끝까지 곱한 수 중 하나가 최대값임                     */
+    /* -------------------------------------------------------------------------- */
+    let frontProduct = 1;
+    let backProduct = 1;
+    for (let i = 0; i < nonZeroNums.length; i++) {
+      if (i < lastNegativeIndex) frontProduct *= nonZeroNums[i];
+      if (i > firstNegativeIndex) backProduct *= nonZeroNums[i];
+    }
+    return Math.max(frontProduct, backProduct);
+  }
+};

missing-number/highball.js

@@ -0,0 +1,8 @@
+//time-complexity : O(n)
+//space-complexity : O(1)
+
+const missingNumber = function (nums) {
+  const sum = nums.reduce((acc, cur) => acc + cur);
+  const n = nums.length;
+  return (n * (n + 1)) / 2 - sum;
+};

valid-palindrome/highball.js

@@ -0,0 +1,27 @@
+//time-complexity : O(n)
+//space-complexity : O(1)
+
+const isPalindrome = function (s) {
+  let left = 0;
+  let right = s.length - 1;
+  while (left < right) {
+    if (isAlphaNumeric(s[left]) && isAlphaNumeric(s[right])) {
+      if (s[left].toLowerCase() === s[right].toLowerCase()) {
+        left++;
+        right--;
+      } else return false;
+    } else {
+      if (!isAlphaNumeric(s[left])) left++;
+      if (!isAlphaNumeric(s[right])) right--;
+    }
+  }
+  return true;
+};
+
+const isAlphaNumeric = function (c) {
+  return (
+    (c.charCodeAt(0) >= 48 && c.charCodeAt(0) <= 57) ||
+    (c.charCodeAt(0) >= 65 && c.charCodeAt(0) <= 90) ||
+    (c.charCodeAt(0) >= 97 && c.charCodeAt(0) <= 122)
+  );
+};

word-search/highball.js

@@ -0,0 +1,42 @@
+//time-complexity : O(4^(ROWS*COLS))
+//space-complexity : O(word.length)
+
+const exist = function (board, word) {
+  const ROWS = board.length;
+  const COLS = board[0].length;
+
+  for (let r = 0; r < ROWS; r++) {
+    for (let c = 0; c < COLS; c++) {
+      if (board[r][c] === word[0]) {
+        if (dfs(board, word, r, c, 0)) return true;
+      }
+    }
+  }
+
+  return false;
+};
+
+const dfs = function (board, word, r, c, i) {
+  const ROWS = board.length;
+  const COLS = board[0].length;
+
+  if (r < 0 || r >= ROWS || c < 0 || c >= COLS || board[r][c] !== word[i]) {
+    return false;
+  }
+
+  if (i === word.length - 1) return true;
+
+  const temp = board[r][c];
+  board[r][c] = null;
+
+  let found =
+    dfs(board, word, r + 0, c + 1, i + 1) ||
+    dfs(board, word, r + 1, c + 0, i + 1) ||
+    dfs(board, word, r + 0, c + -1, i + 1) ||
+    dfs(board, word, r + -1, c + 0, i + 1);
+  //forEach로 했더니 runtime 두 배 됨;;
+
+  board[r][c] = temp;
+
+  return found;
+};