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[Arthur] Week 3 #783

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Dec 28, 2024
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26 changes: 26 additions & 0 deletions product-of-array-except-self/changchanghwang.go
Original file line number Diff line number Diff line change
@@ -0,0 +1,26 @@
// time complexity: O(n)
// space complexity: O(1)
// prefix와 postfix를 이용하여 계산
// 예를 들어, [1, 2, 3, 4] 일 때,
// prefix는 [1, 1, 2, 6] 이고 postfix는 [24, 12, 4, 1] 이다.
// 그리고 서로 곱하면 [24, 12, 8, 6] 이 된다.
func productExceptSelf(nums []int) []int {
res := make([]int, len(nums))
for i := range res {
res[i] = 1
}

prefix := 1
for i := 0; i < len(nums); i++ {
res[i] = prefix
prefix *= nums[i]
}

postfix := 1
for i := len(nums) - 1; i >= 0; i-- {
res[i] *= postfix
postfix *= nums[i]
}

return res
}
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linelint에 걸렸어요~ 😵

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앗... 복붙하다가 실수를했네요... 감사합니다!

6 changes: 6 additions & 0 deletions reverse-bits/changchanghwang.go
Original file line number Diff line number Diff line change
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// Time Complexity: O(1)
// Space Complexity: O(1)
func reverseBits(num uint32) uint32 {
reversedBits := bits.Reverse32(num)
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한 수 배워갑니다 ㅎㅎㅎ

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혹시 될까해서 해봤는데 되더라구요ㅋㅋㅋ....

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내부 구현이 궁금해서 좀 찾아봤는데, 궁금하시면 한 번 구경해보시죠 ㅎㅎ

https://github.com/golang/go/blob/master/src/math/bits/bits.go

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오 이런 함수가 있었군요 ㅎㅎ 덕분에 알아갑니다!

return reversedBits
}
15 changes: 15 additions & 0 deletions two-sum/changchanghwang.go
Original file line number Diff line number Diff line change
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// Time: O(n)
// Space: O(n)
func twoSum(nums []int, target int) []int {
m := make(map[int]int)

// O(n)
for i, num := range nums {
// O(1)
if j, ok := m[target-num]; ok && j != i { // target = num2 + num1 -> num2 = target - num1 을 이용하여 두 수를 찾는다.
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오 정말 간결하군요!

return []int{j, i}
}
m[num] = i // 없다면 현재 수를 키로 하여 인덱스를 저장한다.
}
return nil
}
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