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[Arthur] Week 3 #783
[Arthur] Week 3 #783
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Original file line number | Diff line number | Diff line change |
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// time complexity: O(n) | ||
// space complexity: O(1) | ||
// prefix와 postfix를 이용하여 계산 | ||
// 예를 들어, [1, 2, 3, 4] 일 때, | ||
// prefix는 [1, 1, 2, 6] 이고 postfix는 [24, 12, 4, 1] 이다. | ||
// 그리고 서로 곱하면 [24, 12, 8, 6] 이 된다. | ||
func productExceptSelf(nums []int) []int { | ||
res := make([]int, len(nums)) | ||
for i := range res { | ||
res[i] = 1 | ||
} | ||
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prefix := 1 | ||
for i := 0; i < len(nums); i++ { | ||
res[i] = prefix | ||
prefix *= nums[i] | ||
} | ||
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postfix := 1 | ||
for i := len(nums) - 1; i >= 0; i-- { | ||
res[i] *= postfix | ||
postfix *= nums[i] | ||
} | ||
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return res | ||
} | ||
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// Time Complexity: O(1) | ||
// Space Complexity: O(1) | ||
func reverseBits(num uint32) uint32 { | ||
reversedBits := bits.Reverse32(num) | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 한 수 배워갑니다 ㅎㅎㅎ There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 혹시 될까해서 해봤는데 되더라구요ㅋㅋㅋ.... There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 내부 구현이 궁금해서 좀 찾아봤는데, 궁금하시면 한 번 구경해보시죠 ㅎㅎ https://github.com/golang/go/blob/master/src/math/bits/bits.go There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 오 이런 함수가 있었군요 ㅎㅎ 덕분에 알아갑니다! |
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return reversedBits | ||
} |
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// Time: O(n) | ||
// Space: O(n) | ||
func twoSum(nums []int, target int) []int { | ||
m := make(map[int]int) | ||
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// O(n) | ||
for i, num := range nums { | ||
// O(1) | ||
if j, ok := m[target-num]; ok && j != i { // target = num2 + num1 -> num2 = target - num1 을 이용하여 두 수를 찾는다. | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 오 정말 간결하군요! |
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return []int{j, i} | ||
} | ||
m[num] = i // 없다면 현재 수를 키로 하여 인덱스를 저장한다. | ||
} | ||
return nil | ||
} |
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linelint에 걸렸어요~ 😵
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앗... 복붙하다가 실수를했네요... 감사합니다!