Update README.md

Signed-off-by: Rui Campos <mail@ruicampos.org>

README.md

@@ -58,7 +58,7 @@ $$\rho^{nul} = \delta^{f(u)g(u)} p^{nf(u)f(l)} p^{nf(u)g(l)} + 2  \tilde \delta^
 Substituting this back, while attending to the relevant substitution on the first term of the original expression,
 
 
-$$q^{nul} _ {l} = \delta_{f(l)g(l)} \bar M^n_{l} \left [ \delta^{f(u)g(u)} p^{nf(u)f(l)} p^{nf(u)f(l)} + 2  \tilde \delta^{f(u)g(u)}   p^{nf(u)f(l)} p^{ng(u)f(l)} \right ]  + 2 \tilde \delta_{f(l)g(l)}   \bar M^n_l \left [ \delta^{f(u)g(u)} p^{nf(u)f(l)} p^{nf(u)g(l)} + 2  \tilde \delta^{f(u)g(u)}   p^{nf(u)f(l)} p^{ng(u)g(l)} \right ]$$
+$$q^{nul} _ {l} = \delta^{f(l)g(l)} \bar M^n_{l} \left [ \delta^{f(u)g(u)} p^{nf(u)f(l)} p^{nf(u)f(l)} + 2  \tilde \delta^{f(u)g(u)}   p^{nf(u)f(l)} p^{ng(u)f(l)} \right ]  + 2 \tilde \delta^{f(l)g(l)}   \bar M^n_l \left [ \delta^{f(u)g(u)} p^{nf(u)f(l)} p^{nf(u)g(l)} + 2  \tilde \delta^{f(u)g(u)}   p^{nf(u)f(l)} p^{ng(u)g(l)} \right ]$$
 
 which we'll now group according to the $\delta$'s