-
Notifications
You must be signed in to change notification settings - Fork 1k
/
Copy pathtotal_subtrees.cpp
128 lines (115 loc) · 2.31 KB
/
total_subtrees.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
/*Problem Statement:
We are given a binary tree having N+1 nodes, N edges and an integer x.
The task is to find the count of the total number of subtrees having total node's
data sum equal to value X. */
#include<bits/stdc++.h>
using namespace std;
char a[1000];
vector<int> v;
class Node
{
public:
int data;
Node*left;
Node*right;
Node(int d)
{
data = d;
left = right = NULL;
}
};
void StringToNums()
{
//Dividing the string characters by a space
char *ans=strtok(a," ");
while(ans!=NULL)
{
//The corresponding integer of the character is being pushed
v.push_back(stoi(ans));
ans=strtok(NULL," ");
}
}
Node* CreateTree()
{
if(strlen(a)==0 or v.size()==0)
{
return NULL;
}
int no=v[0];
Node* root=new Node(no);
int i=1;
queue<Node*> q;
q.push(root);
while(!q.empty() and i<v.size())
{
Node* temp=q.front();
q.pop();
no=v[i];
i++;
temp->left=new Node(no);
q.push(temp->left);
if(i>=v.size())
{
break;
}
//If elements are remaining in the array, then make it the right child
no=v[i++];
temp->right=new Node(no);
q.push(temp->right);
if(i>=v.size())
{
break;
}
}
return root;
}
int Sum(Node* root)
{
if(root==NULL)
{
return 0;
}
int left=Sum(root->left);
int right=Sum(root->right);
return root->data+left+right;
}
int countSubtrees(Node* root,int x)
{
if(root==NULL)
{
return 0;
}
int ans=0;
/*If the data value of the node+left child+right child is equal to x,
then we have found the subtree */
if(Sum(root)==x)
{
ans=1;
}
int left=countSubtrees(root->left,x);
int right=countSubtrees(root->right,x);
return ans+left+right;
}
int main()
{
int x;
cin.ignore();
cout<<"Enter the nodes of the tree: "<<endl;
cin.getline(a,1000);
cout<<"Enter the value x: "<<endl;
StringToNums();
Node* root=CreateTree();
cout<<"Total subtrees are: "<<countSubtrees(root,x)<<endl;
return 0;
}
/*Example:-
Input:-
Enter the nodes of the tree:
1 2 3
Enter the value x:
5
Output:-
Total subtrees are: 0
Time Complexity: O(n)
Space Complexity: O(n)
*/