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kbordermatrix.sty
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kbordermatrix.sty
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\NeedsTeXFormat{LaTeX2e}
\ProvidesPackage{kbordermatrix}[2011/09/21 Bordered matrix with brackets]
% Author: Kim C Border <kcborder@caltech.edu>
% Date: SuperBowl XXXVII (Go Bucs)
% Revised 2003/09/20
% to allow flush right option.
% Revised 2011/09/21
% at urging of Bruno Calfa (CMU)
% to coexist with package arydshln
% by adding \def\@xarraycr ...
% Defines \kbordermatrix along the lines of plain tex's
% \bordermatrix (which is still available in LaTeX).
% In particular, as with \bordermatrix,
% 1. It takes the array as an argument. It does not use \begin{}..\end{}.
% Is this a feature or a bug?
% 2. The first row is spaced a bit further apart from the rest.
% 3. The lower (n-1) by (n-1) block is set off by delimiters.
% 4. There is an invisible bottom row of the same height as the segregated
% top row that adds to the height of the equation.
% Differences from \bordermatrix:
% 1. Square brackets are used in place of parentheses.
% 2. You may use \\ instead of \cr.
% 3. The line heights agree with LaTeX's line heights for the
% array environment, and \arraystretch is respected. This means
% the bottom (n-1) rows align with the rows of an (n-1)-rowed
% \begin{array}..\end{array} (with or without delimiters).
% 4. All columns are centered.
% ** Modified 2003-9-20 to allow flush right option.
% 5. The first column is spaced a bit further apart from the rest.
% Differences from \left\[\begin{array}...\end{array}\right\]
% 1. It takes the array as an argument. It does not use \begin{}..\end{}.
% Is this a feature or a bug?
% 2. Consequently, you cannot use a column specifier (e.g., {l|cr}).
% 3. Consequently the maximum number of columns is not specified.
% 4. Vertical rules must be put in each row in a separate column.
% 5. You can use \hline and \cline.
% At least it works in the cases I have tried, but I offer no guarantees.
% cf. \bordermatrix p. 361, and \vrulealign p. 392 of The TeXbook
% Style parameters, they may be redefined according to taste.
\newcommand{\kbldelim}{[} % Left delimiter
\newcommand{\kbrdelim}{]}% Right delimiter
\newcommand{\kbrowstyle}{\scriptstyle}% Style applied to first row
\newcommand{\kbcolstyle}{\scriptstyle}% Style applied to first column
\newlength{\kbcolsep} % Extra separation after first border column
\newlength{\kbrowsep} % Extra separation after first border row
\setlength{\kbcolsep}{.5\arraycolsep}
\setlength{\kbrowsep}{.2ex}
\newif\ifkbalignright
% Scratch lengths (to be computed)
\newlength{\br@kwd} % Width of delimiter
\newlength{\k@bordht} % Height of border column
% This is it
\newcommand{\kbordermatrix}[1]{%
\begingroup
% \br@kwd depends on font size, so compute it now.
\setbox0=\hbox{$\left\kbldelim\right.$}
\setlength{\br@kwd}{\wd0}
% Compute the array strut based on current value of \arraystretch.
\setbox\@arstrutbox\hbox{\vrule
\@height\arraystretch\ht\strutbox
\@depth\arraystretch\dp\strutbox
\@width\z@}
% Compute height of first row and extra space.
\setlength{\k@bordht}{\kbrowsep}
\addtolength{\k@bordht}{\ht\@arstrutbox}
\addtolength{\k@bordht}{\dp\@arstrutbox}
% turn off mathsurround
\m@th
% Set the first row style
\def\@kbrowstyle{\kbrowstyle}
% Swallow the alignment into box0:
\setbox0=\vbox{%
% Define \cr for first row to include the \kbrowsep
% and to reset the row style
\def\cr{\crcr\noalign{\kern\kbrowsep
\global\let\cr=\endline
\global\let\@kbrowstyle=\relax}}
% Redefine \\ a la LaTeX:
\let\\\@arraycr
% The following are needed to make a solid \vrule with no gaps
% between the lines.
\lineskip\z@skip
\baselineskip\z@skip
% Compute the length of the skip after the first column
\dimen0\kbcolsep \advance\dimen0\br@kwd
% Here begins the alignment:
\ialign{\tabskip\dimen0 % This space will show up after the first column
\kern\arraycolsep\hfil\@arstrut$\kbcolstyle ##$\hfil\kern\arraycolsep&
\tabskip\z@skip % Cancel extra space for other columns
\kern\arraycolsep\hfil$\@kbrowstyle ##$\ifkbalignright\relax\else\hfil\fi\kern\arraycolsep&&
\kern\arraycolsep\hfil$\@kbrowstyle ##$\ifkbalignright\relax\else\hfil\fi\kern\arraycolsep\crcr
% That ends the template.
% Here is the argument:
#1\crcr}% End \ialign
}% End \setbox0.
% \box0 now holds the array.
%
% This next line uses \box2 to hold a throwaway
% copy of \box0, leaving \box0 intact,
% while putting the last row in \box5.
\setbox2=\vbox{\unvcopy0 \global\setbox5=\lastbox}
% We want the width of the first column,
% so we lop off columns until there is only one left.
% It's not elegant or efficient, but at 1 gHz, who cares.
\loop
\setbox2=\hbox{\unhbox5 \unskip \global\setbox3=\lastbox}
\ifhbox3
\global\setbox5=\box2
\global\setbox1=\box3
\repeat
% \box1 now holds the first column of last row.
%
% This next line stores the alignment in \box2,
% while calculating the proper
% delimiter height and placement.
\setbox2=\hbox{$\kern\wd1\kern\kbcolsep\kern-\arraycolsep
\left\kbldelim
\kern-\wd1\kern-\kbcolsep\kern-\br@kwd
%
% Here is the output. The \vcenter aligns the array with the "math axis."
% The negative vertical \kern only shrinks the delimiter's height.
% BTW, I didn't find this in the TeXbook,
% I had to try various \kerns to see what they did in a
% \left[\vcenter{}\right].
\vcenter{\kern-\k@bordht\vbox{\unvbox0}}
\right\kbrdelim$}
\null\vbox{\kern\k@bordht\box2}
%
\endgroup
}