Given a binary array, find the maximum number of consecutive 1s in this array.
Detail instruction can be found here.
Example 1:
Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
The maximum number of consecutive 1s is 3.
public int findMaxConsecutiveOnes(int[] nums) {
int res = 0;
for (int i = 0, j = 0; i < nums.length; i++) {
if (nums[i] == 0) {
j = i + 1;
} else {
res = Math.max(res, i - j + 1);
}
}
return res;
}
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