Kangaroo.py

# You are choreographing a circus show with various animals. For one act, you are given two kangaroos on a number line ready to jump in the positive direction (i.e, toward positive infinity).

# The first kangaroo starts at location  and moves at a rate of  meters per jump.
# The second kangaroo starts at location  and moves at a rate of  meters per jump.
# You have to figure out a way to get both kangaroos at the same location at the same time as part of the show. If it is possible, return YES, otherwise return NO.

# For example, kangaroo  starts at  with a jump distance  and kangaroo  starts at  with a jump distance of . After one jump, they are both at , (, ), so our answer is YES.

# Function Description

# Complete the function kangaroo in the editor below. It should return YES if they reach the same position at the same time, or NO if they don't.

# kangaroo has the following parameter(s):

# x1, v1: integers, starting position and jump distance for kangaroo 1
# x2, v2: integers, starting position and jump distance for kangaroo 2
# Input Format

# A single line of four space-separated integers denoting the respective values of , , , and .

# Constraints

# Output Format

# Print YES if they can land on the same location at the same time; otherwise, print NO.

# Note: The two kangaroos must land at the same location after making the same number of jumps.

# Sample Input 0

# 0 3 4 2
# Sample Output 0

# YES
# Explanation 0

# The two kangaroos jump through the following sequence of locations:

# image

# From the image, it is clear that the kangaroos meet at the same location (number  on the number line) after same number of jumps ( jumps), and we print YES.

# Sample Input 1

# 0 2 5 3
# Sample Output 1

# NO
# Explanation 1

# The second kangaroo has a starting location that is ahead (further to the right) of the first kangaroo's starting location (i.e., ). Because the second kangaroo moves at a faster rate (meaning ) and is already ahead of the first kangaroo, the first kangaroo will never be able to catch up. Thus, we print NO.








#!/bin/python3

import math
import os
import random
import re
import sys

# Complete the kangaroo function below.

def kangaroo(x1, v1, x2, v2):
    i = 10000
    counter = 0
    while(i > 0):
        if(x1 == x2):
            return "YES"
            counter = 1
            break
        else:
            x1 += v1
            x2 += v2
            i -= 1
    if(counter == 0):
        return "NO"


if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')

    x1V1X2V2 = input().split()

    x1 = int(x1V1X2V2[0])

    v1 = int(x1V1X2V2[1])

    x2 = int(x1V1X2V2[2])

    v2 = int(x1V1X2V2[3])

    result = kangaroo(x1, v1, x2, v2)

    fptr.write(result + '\n')

    fptr.close()