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rectangle overlap when no corners within bug fix #99
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AnushaTiwari5
added
the
Bug
Something isn't working. Rightmost number in semantic versioning
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Oct 9, 2023
James-Oswald
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Oct 9, 2023
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+105
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+141
/** | ||
* Checks if any of the horizontal edges of the other rectangle lie within the horizontal | ||
* boundaries of this rectangle | ||
* @param otherRect The other rectangle | ||
* @returns True, if the other edges lie within this boundary. Else, false | ||
*/ | ||
private checkHorizontalEdgeOverlap(otherRect: Rectangle): boolean { | ||
const thisCorners = this.getCorners(); | ||
const otherCorners = otherRect.getCorners(); | ||
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if (thisCorners[0].y <= otherCorners[0].y && thisCorners[2].y >= otherCorners[0].y) { | ||
return true; | ||
} else if (thisCorners[0].y <= otherCorners[2].y && thisCorners[2].y >= otherCorners[2].y) { | ||
return true; | ||
} | ||
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return false; | ||
} | ||
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/** | ||
* Checks if any of the vertical edges of the other rectangle lie within the vertical | ||
* boundaries of this rectangle | ||
* @param otherRect The other rectangle | ||
* @returns True, if the other edges lie within this boundary. Else, false | ||
*/ | ||
private checkVerticalEdgeOverlap(otherRect: Rectangle): boolean { | ||
const thisCorners = this.getCorners(); | ||
const otherCorners = otherRect.getCorners(); | ||
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if (thisCorners[0].x <= otherCorners[0].x && thisCorners[1].x >= otherCorners[0].x) { | ||
return true; | ||
} else if (thisCorners[0].x <= otherCorners[1].x && thisCorners[1].x >= otherCorners[1].x) { | ||
return true; | ||
} | ||
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return false; | ||
} |
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This code is repetitive, we can abstract this into a single function.
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Fixed and tested, I believe this should detect collision even when the corners of the bounding boxes are not within the other.