-
Notifications
You must be signed in to change notification settings - Fork 0
/
p185.java
49 lines (34 loc) · 1.04 KB
/
p185.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
/*Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive.
There is only one repeated number in nums, return this repeated number.
You must solve the problem without modifying the array nums and uses only constant extra space.
Example 1:
Input: nums = [1,3,4,2,2]
Output: 2
Example 2:
Input: nums = [3,1,3,4,2]
Output: 3
Constraints:
1 <= n <= 105
nums.length == n + 1
1 <= nums[i] <= n
All the integers in nums appear only once except for precisely one integer which appears two or more times.
Follow up:
How can we prove that at least one duplicate number must exist in nums?
Can you solve the problem in linear runtime complexity?*/
class Solution {
public int findDuplicate(int[] nums) {
int n=nums.length;
int i=nums[0];
int j=nums[0];
do{
i=nums[i];
j=nums[nums[j]];
}while(i!=j);
j=nums[0];
while(i!=j){
i=nums[i];
j=nums[j];
}
return i;
}
}