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feat: bv<-->av 增加java实现 (#1021)
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cctyl authored May 20, 2024
1 parent e6dc29e commit 11d4285
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81 changes: 81 additions & 0 deletions docs/misc/bvid_desc.md
Original file line number Diff line number Diff line change
Expand Up @@ -248,6 +248,87 @@ print(av2bv(avid: 111298867365120))
print(bv2av(bvid: "BV1L9Uoa9EUx"))
```


### Java

```
import java.math.BigInteger;
/**
* @author cctyl
*/
public class AVBVConverter {
private static final BigInteger XOR_CODE = BigInteger.valueOf(23442827791579L);
private static final BigInteger MASK_CODE = BigInteger.valueOf(2251799813685247L);
private static final BigInteger MAX_AID = BigInteger.ONE.shiftLeft(51);
private static final int BASE = 58;
private static final String DATA = "FcwAPNKTMug3GV5Lj7EJnHpWsx4tb8haYeviqBz6rkCy12mUSDQX9RdoZf";
public static String av2bv(int aidParam) {
BigInteger aid = BigInteger.valueOf(aidParam);
char[] bytes = {'B', 'V', '1', '0', '0', '0', '0', '0', '0', '0', '0', '0'};
int bvIndex = bytes.length - 1;
BigInteger tmp = MAX_AID.or(aid).xor(XOR_CODE);
while (tmp.compareTo(BigInteger.ZERO) > 0) {
bytes[bvIndex] = DATA.charAt(tmp.mod(BigInteger.valueOf(BASE)).intValue());
tmp = tmp.divide(BigInteger.valueOf(BASE));
bvIndex -= 1;
}
swap(bytes, 3, 9);
swap(bytes, 4, 7);
StringBuilder sb = new StringBuilder(bytes.length);
for (Character ch : bytes) {
sb.append(ch);
}
return sb.toString();
}
public static int bv2av(String bvid) {
char[] bvidArr = bvid.toCharArray();
swap(bvidArr, 3, 9);
swap(bvidArr, 4, 7);
String adjustedBvid = new String(bvidArr, 3, bvidArr.length - 3);
BigInteger tmp = BigInteger.ZERO;
for (char c : adjustedBvid.toCharArray()) {
tmp = tmp.multiply(BigInteger.valueOf(BASE)).add(BigInteger.valueOf(DATA.indexOf(c)));
}
BigInteger xor = tmp.and(MASK_CODE).xor(XOR_CODE);
return xor.intValue();
}
private static void swap(char[] array, int i, int j) {
char temp = array[i];
array[i] = array[j];
array[j] = temp;
}
public static void main(String[] args) {
final int aid1 = 643755790;
final String bv1 = "BV1bY4y1j7RA";
final int aid2 = 305988942;
final String bv2 = "BV1aP411K7it";
//av ==> bv
assert av2bv(aid1).equals(bv1);
assert av2bv(aid2).equals(bv2);
//bv ==>av
assert bv2av(bv1) == aid1;
assert bv2av(bv2) == aid2;
}
}
```


## 老版算法存档

**以下算法已失效**,编解码函数值域有限,不推荐使用,在此仅作为存档
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