From 381a16856d2bcf23afd00eb0fcaf84ce9f627cc3 Mon Sep 17 00:00:00 2001 From: YanceyOfficial Date: Tue, 14 Nov 2023 20:29:33 +0800 Subject: [PATCH] feat: finish 99-recover-tree --- leetcode-docs/medium/95-generate-trees.mdx | 5 + leetcode-docs/medium/96-num-trees.mdx | 17 ++- leetcode-docs/medium/99-recover-tree.mdx | 103 ++++++++++++++++++ ...11\346\220\234\347\264\242\346\240\221.js" | 14 ++- ...11\346\220\234\347\264\242\346\240\221.js" | 60 ++++++++++ src/leetcode/rust/src/medium/mod.rs | 5 +- src/leetcode/rust/src/medium/question_99.rs | 1 + static/img/99-recover-tree-1.jpg | Bin 0 -> 14332 bytes static/img/99-recover-tree-2.jpg | Bin 0 -> 19255 bytes 9 files changed, 200 insertions(+), 5 deletions(-) create mode 100644 leetcode-docs/medium/99-recover-tree.mdx create mode 100644 "src/leetcode/javascript/medium/99.\346\201\242\345\244\215\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.js" create mode 100644 src/leetcode/rust/src/medium/question_99.rs create mode 100644 static/img/99-recover-tree-1.jpg create mode 100644 static/img/99-recover-tree-2.jpg diff --git a/leetcode-docs/medium/95-generate-trees.mdx b/leetcode-docs/medium/95-generate-trees.mdx index a0406708..d707eb6d 100644 --- a/leetcode-docs/medium/95-generate-trees.mdx +++ b/leetcode-docs/medium/95-generate-trees.mdx @@ -78,3 +78,8 @@ var generateTrees = function (n) { return dfs(1, n) } ``` + +## 复杂度分析 + +- 时间复杂度：卡特兰数 +- 空间复杂度: 卡特兰数 diff --git a/leetcode-docs/medium/96-num-trees.mdx b/leetcode-docs/medium/96-num-trees.mdx index fcba45c4..b58ed937 100644 --- a/leetcode-docs/medium/96-num-trees.mdx +++ b/leetcode-docs/medium/96-num-trees.mdx @@ -38,12 +38,25 @@ keywords: ## 题解 -这里是题解这里是题解这里是题解这里是题解这里是题解 +给定一个有序序列 `1` 到 `n`,为了构建出一棵二叉搜索树, 我们可以遍历每个数字 `i`, 将该数字作为树根, 将 `1` 到 `i - 1` 序列作为左子树，将 `i + 1` 到 `n` 序列作为右子树. +接着我们可以按照同样的方式递归构建左子树和右子树. ```ts /** * @param {number} n * @return {number} */ -var numTrees = function (n) {} +var numTrees = function (n) { + const dp = new Array(n + 1).fill(0) + dp[0] = 1 + dp[1] = 1 + + for (let i = 2; i <= n; i++) { + for (let j = 1; j <= i; j++) { + dp[i] += dp[j - 1] * dp[i - j] + } + } + + return dp[n] +} ``` diff --git a/leetcode-docs/medium/99-recover-tree.mdx b/leetcode-docs/medium/99-recover-tree.mdx new file mode 100644 index 00000000..4533e707 --- /dev/null +++ b/leetcode-docs/medium/99-recover-tree.mdx @@ -0,0 +1,103 @@ +--- +id: 99-recover-tree +title: 恢复二叉搜索树 +sidebar_label: 99. 恢复二叉搜索树 +keywords: + - Tree, BST +--- + +:::success Tips +题目类型: Tree, BST +::: + +## 题目 + +给你二叉搜索树的根节点 `root`. 该树中的**恰好两个节点**的值被错误地交换. 请在不改变其结构的情况下, 恢复这棵树. + +:::note 提示: + +- 树上节点的数目在范围 `[2, 1000]` 内 +- `-2³¹ <= Node.val <= 2³¹ - 1` + +::: + +:::info 示例 + +![33-search](../../static/img/99-recover-tree-1.jpg) + +```ts +输入：root = [1,3,null,null,2] +输出：[3,1,null,null,2] +解释：3 不能是 1 的左孩子，因为 3 > 1 。交换 1 和 3 使二叉搜索树有效。 +``` + +![33-search](../../static/img/99-recover-tree-2.jpg) + +```ts +输入：root = [3,1,4,null,null,2] +输出：[2,1,4,null,null,3] +解释：2 不能在 3 的右子树中，因为 2 < 3 。交换 2 和 3 使二叉搜索树有效。 +``` + +::: + +## 题解 + +1. 由于是 BST, 所以使用中序遍历, 把所有节点存储到 `list` 中 +2. 遍历这个列表 `list`, 由于 BST 的中序遍历应当是从小到大排列的, 所以如果前面的 val 大于了后面的 val, 说明后面这个应当靠前. +3. 找到两个需要交换的, 交换他们的值即可 + +```ts +/** + * Definition for a binary tree node. + * function TreeNode(val, left, right) { + * this.val = (val===undefined ? 0 : val) + * this.left = (left===undefined ? null : left) + * this.right = (right===undefined ? null : right) + * } + */ +/** + * @param {TreeNode} root + * @return {void} Do not return anything, modify root in-place instead. + */ +var recoverTree = function (root) { + const list = [] + inOrder(root, list) + let x = null + let y = null + + for (let i = 0; i < list.length - 1; i++) { + if (list[i].val > list[i + 1].val) { + y = list[i + 1] + if (!x) x = list[i] + } + } + + if (x && y) { + const tmp = x.val + x.val = y.val + y.val = tmp + } +} + +/** + * Definition for a binary tree node. + * function TreeNode(val, left, right) { + * this.val = (val===undefined ? 0 : val) + * this.left = (left===undefined ? null : left) + * this.right = (right===undefined ? null : right) + * } + */ +/** + * @param {TreeNode} root + * @param {TreeNode[]} list + * @return {void} Do not return anything, modify root in-place instead. + */ +var inOrder = function (root, list) { + if (!root) return null + + inOrder(root.left, list) + list.push(root) + inOrder(root.right, list) +} +``` diff --git "a/src/leetcode/javascript/medium/96.\344\270\215\345\220\214\347\232\204\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.js" "b/src/leetcode/javascript/medium/96.\344\270\215\345\220\214\347\232\204\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.js" index 0ca0f335..395a7bb0 100644 --- "a/src/leetcode/javascript/medium/96.\344\270\215\345\220\214\347\232\204\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.js" +++ "b/src/leetcode/javascript/medium/96.\344\270\215\345\220\214\347\232\204\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.js" @@ -9,5 +9,17 @@ * @param {number} n * @return {number} */ -var numTrees = function (n) {} +var numTrees = function (n) { + const dp = new Array(n + 1).fill(0) + dp[0] = 1 + dp[1] = 1 + + for (let i = 2; i <= n; i++) { + for (let j = 1; j <= i; j++) { + dp[i] += dp[j - 1] * dp[i - j] + } + } + + return dp[n] +} // @lc code=end diff --git "a/src/leetcode/javascript/medium/99.\346\201\242\345\244\215\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.js" "b/src/leetcode/javascript/medium/99.\346\201\242\345\244\215\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.js" new file mode 100644 index 00000000..05f559b8 --- /dev/null +++ "b/src/leetcode/javascript/medium/99.\346\201\242\345\244\215\344\272\214\345\217\211\346\220\234\347\264\242\346\240\221.js" @@ -0,0 +1,60 @@ +/* + * @lc app=leetcode.cn id=99 lang=javascript + * + * [99] 恢复二叉搜索树 + */ + +// @lc code=start +/** + * Definition for a binary tree node. + * function TreeNode(val, left, right) { + * this.val = (val===undefined ? 0 : val) + * this.left = (left===undefined ? null : left) + * this.right = (right===undefined ? null : right) + * } + */ +/** + * @param {TreeNode} root + * @return {void} Do not return anything, modify root in-place instead. + */ +var recoverTree = function (root) { + const list = [] + inOrder(root, list) + let x = null + let y = null + + for (let i = 0; i < list.length - 1; i++) { + if (list[i].val > list[i + 1].val) { + y = list[i + 1] + if (!x) x = list[i] + } + } + + if (x && y) { + const tmp = x.val + x.val = y.val + y.val = tmp + } +} + +/** + * Definition for a binary tree node. + * function TreeNode(val, left, right) { + * this.val = (val===undefined ? 0 : val) + * this.left = (left===undefined ? null : left) + * this.right = (right===undefined ? null : right) + * } + */ +/** + * @param {TreeNode} root + * @param {TreeNode[]} list + * @return {void} Do not return anything, modify root in-place instead. + */ +var inOrder = function (root, list) { + if (!root) return null + + inOrder(root.left, list) + list.push(root) + inOrder(root.right, list) +} +// @lc code=end diff --git a/src/leetcode/rust/src/medium/mod.rs b/src/leetcode/rust/src/medium/mod.rs index 3594efb6..4b4e578e 100644 --- a/src/leetcode/rust/src/medium/mod.rs +++ b/src/leetcode/rust/src/medium/mod.rs @@ -1,5 +1,4 @@ pub mod question_11; -pub mod question_2; pub mod question_1143; pub mod question_12; pub mod question_120; @@ -11,6 +10,7 @@ pub mod question_16; pub mod question_17; pub mod question_19; pub mod question_198; +pub mod question_2; pub mod question_213; pub mod question_215; pub mod question_22; @@ -87,4 +87,5 @@ pub mod question_90; pub mod question_91; pub mod question_926; pub mod question_93; -pub mod question_97; \ No newline at end of file +pub mod question_97; +pub mod question_99; \ No newline at end of file diff --git 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