-
Notifications
You must be signed in to change notification settings - Fork 0
/
290_Word_Pattern.java
53 lines (51 loc) · 1.37 KB
/
290_Word_Pattern.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
// Given a pattern and a string str, find if str follows the same pattern.
//
// Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.
//
// Example 1:
//
//
// Input: pattern = "abba", str = "dog cat cat dog"
// Output: true
//
// Example 2:
//
//
// Input:pattern = "abba", str = "dog cat cat fish"
// Output: false
//
// Example 3:
//
//
// Input: pattern = "aaaa", str = "dog cat cat dog"
// Output: false
//
// Example 4:
//
//
// Input: pattern = "abba", str = "dog dog dog dog"
// Output: false
//
// Notes:
// You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.
class Solution {
public boolean wordPattern(String pattern, String str) {
String [] count=str.split(" ");
if(pattern.length()!=count.length) return false;
Map <Character,String> map=new HashMap<>();
for(int i=0;i<pattern.length();i++){
if(map.containsKey(pattern.charAt(i))){
if(!map.get(pattern.charAt(i)).equals(count[i])){
return false;
}
}else{
if(map.containsValue(count[i])){
return false;
}else{
map.put(pattern.charAt(i),count[i]);
}
}
}
return true;
}
}