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155.最小栈.java
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155.最小栈.java
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import java.util.Stack;
/*
* @lc app=leetcode.cn id=155 lang=java
*
* [155] 最小栈
*
* https://leetcode-cn.com/problems/min-stack/description/
*
* algorithms
* Easy (52.12%)
* Likes: 459
* Dislikes: 0
* Total Accepted: 96.7K
* Total Submissions: 183.7K
* Testcase Example: '["MinStack","push","push","push","getMin","pop","top","getMin"]\n' +
'[[],[-2],[0],[-3],[],[],[],[]]'
*
* 设计一个支持 push ,pop ,top 操作,并能在常数时间内检索到最小元素的栈。
*
*
* push(x) —— 将元素 x 推入栈中。
* pop() —— 删除栈顶的元素。
* top() —— 获取栈顶元素。
* getMin() —— 检索栈中的最小元素。
*
*
*
*
* 示例:
*
* 输入:
* ["MinStack","push","push","push","getMin","pop","top","getMin"]
* [[],[-2],[0],[-3],[],[],[],[]]
*
* 输出:
* [null,null,null,null,-3,null,0,-2]
*
* 解释:
* MinStack minStack = new MinStack();
* minStack.push(-2);
* minStack.push(0);
* minStack.push(-3);
* minStack.getMin(); --> 返回 -3.
* minStack.pop();
* minStack.top(); --> 返回 0.
* minStack.getMin(); --> 返回 -2.
*
*
*
*
* 提示:
*
*
* pop、top 和 getMin 操作总是在 非空栈 上调用。
*
*
*/
// @lc code=start
class MinStack {
Stack<Integer> data;
Stack<Integer> min;
/** initialize your data structure here. */
public MinStack() {
data = new Stack<Integer>();
min = new Stack<Integer>();
}
public void push(int x) {
data.push(x);
if (!min.isEmpty()) {
int top = min.peek();
if (top >= x) {
min.push(x);
}
} else {
min.push(x);
}
}
public void pop() {
int temp = 0;
if (!data.isEmpty()) {
temp = data.pop();
}
if (!min.isEmpty()) {
if (min.peek() == temp) {
min.pop();
}
}
}
public int top() {
return data.peek();
}
public int getMin() {
if (!min.isEmpty()) {
return min.peek();
}
throw new IndexOutOfBoundsException("越界了");
}
}
/**
* Your MinStack object will be instantiated and called as such: MinStack obj =
* new MinStack(); obj.push(x); obj.pop(); int param_3 = obj.top(); int param_4
* = obj.getMin();
*/
// @lc code=end