-
Notifications
You must be signed in to change notification settings - Fork 68
/
Copy pathPrinterError.rb
44 lines (33 loc) · 1.26 KB
/
PrinterError.rb
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
=begin
In a factory a printer prints labels for boxes. For one kind of boxes
the printer has to use colors which, for the sake of simplicity,
are named with letters from a to m.
The colors used by the printer are recorded in a control string.
For example a "good" control string would be aaabbbbhaijjjm meaning
that the printer used three times color a, four times color b,
then one time color a...
Sometimes there are problems: lack of colors, technical malfunction
and a "bad" control string is produced e.g. aaaxbbbbyyhwawiwjjjwwm.
You have to write a function printer_error which given a string will
output the error rate of the printer as a string representing a
rational whose numerator is the number of errors and the denominator
the length of the control string. Don't reduce this fraction to a
simpler expression.
The string has a length greater or equal to one and contains only
letters from ato z.
Examples:
s="aaabbbbhaijjjm"
error_printer(s) => "0/14"
s="aaaxbbbbyyhwawiwjjjwwm"
error_printer(s) => "8/22"
=end
# My Solution
def printer_error(s)
good = s.count "abcdefghijklm"
bad = s.count "nopqrstuvwxyz"
(s.count "nopqrstuvwxyz").to_s ? "#{bad}/#{s.length}" : "0/#{good}"
end
# Better Solution
def printer_error(s)
"#{s.count('n-z')}/#{s.length}"
end