transformer_sizing.ipynb

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   "source": [
    "### Transformer Theoretical Model\n",
    "\n",
    "这个笔记本存储了关于一个Transformer的大量分析，例如估算浮点运算次数、参数数量、内存峰值占用、检查点大小,MFU (model flops utilization)等。"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [],
   "source": [
    "from collections import OrderedDict"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [],
   "source": [
    "# config_args = {\n",
    "#     'gpt2':         dict(n_layer=12, n_head=12, n_embd=768),  # 124M params\n",
    "#     'gpt2-medium':  dict(n_layer=24, n_head=16, n_embd=1024), # 350M params\n",
    "#     'gpt2-large':   dict(n_layer=36, n_head=20, n_embd=1280), # 774M params\n",
    "#     'gpt2-xl':      dict(n_layer=48, n_head=25, n_embd=1600), # 1558M params\n",
    "# }[model_type]\n",
    "\n",
    "block_size = 1024\n",
    "vocab_size = 50257\n",
    "n_layer = 12\n",
    "n_head = 12\n",
    "n_embd = 768\n",
    "bias = False\n",
    "assert not bias, \"this notebook assumes bias=False just for simplicity\""
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "we see: 124337664, expected: 124337664, match: True\n",
      "name                 params     ratio (%) \n",
      "emebedding/position      786432     0.6325\n",
      "embedding/token        38597376    31.0424\n",
      "embedding              39383808    31.6749\n",
      "attention/ln                768     0.0006\n",
      "attention/kqv           1769472     1.4231\n",
      "attention/proj           589824     0.4744\n",
      "attention               2360064     1.8981\n",
      "mlp/ln                      768     0.0006\n",
      "mlp/ffw                 2359296     1.8975\n",
      "mlp/proj                2359296     1.8975\n",
      "mlp                     4719360     3.7956\n",
      "block                   7079424     5.6937\n",
      "transformer            84953088    68.3245\n",
      "ln_f                        768     0.0006\n",
      "dense                         0     0.0000\n",
      "total                 124337664   100.0000\n"
     ]
    }
   ],
   "source": [
    "def params():\n",
    "    \"\"\" estimates the number of parameters in the model\"\"\"\n",
    "    out = OrderedDict()\n",
    "\n",
    "    # token and position embeddings\n",
    "    out['emebedding/position'] = n_embd * block_size\n",
    "    out['embedding/token'] = n_embd * vocab_size\n",
    "    out['embedding'] = out['emebedding/position'] + out['embedding/token']\n",
    "\n",
    "    # attention blocks\n",
    "    out['attention/ln'] = n_embd # note, bias=False in our LN\n",
    "    out['attention/kqv'] = n_embd * 3*n_embd\n",
    "    out['attention/proj'] = n_embd**2\n",
    "    out['attention'] = out['attention/ln'] + out['attention/kqv'] + out['attention/proj']\n",
    "\n",
    "    # MLP blocks\n",
    "    ffw_size = 4*n_embd # feed forward size\n",
    "    out['mlp/ln'] = n_embd\n",
    "    out['mlp/ffw'] = n_embd * ffw_size\n",
    "    out['mlp/proj'] = ffw_size * n_embd\n",
    "    out['mlp'] = out['mlp/ln'] + out['mlp/ffw'] + out['mlp/proj']\n",
    "    \n",
    "    # the transformer and the rest of it\n",
    "    out['block'] = out['attention'] + out['mlp']\n",
    "    out['transformer'] = n_layer * out['block']\n",
    "    out['ln_f'] = n_embd # final layernorm\n",
    "    out['dense'] = 0 # 0 because of parameter sharing. This layer uses the weights from the embedding layer\n",
    "\n",
    "    # total\n",
    "    out['total'] = out['embedding'] + out['transformer'] + out['ln_f'] + out['dense']\n",
    "\n",
    "    return out\n",
    "\n",
    "# compare our param count to that reported by PyTorch\n",
    "p = params()\n",
    "params_total = p['total']\n",
    "print(f\"we see: {params_total}, expected: {124337664}, match: {params_total == 124337664}\")\n",
    "# create a header\n",
    "print(f\"{'name':20s} {'params':10s} {'ratio (%)':10s}\")\n",
    "for k,v in p.items():\n",
    "    print(f\"{k:20s} {v:10d} {v/params_total*100:10.4f}\")\n",
    "    "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "est checkpoint size: 1.49 GB\n",
      "measured with wc -c ckpt.pt: 1542470366\n",
      "fluff ratio: 103.38%\n"
     ]
    }
   ],
   "source": [
    "# we can now calculate the size of each checkpoint\n",
    "# params are stored in fp32, and the AdamW optimizer has 2 additional buffers per param for statistics\n",
    "params_bytes = params_total*4\n",
    "params_and_buffers_bytes = params_bytes + 2*params_bytes\n",
    "print(f\"est checkpoint size: {params_and_buffers_bytes/1e9:.2f} GB\")\n",
    "measured_bytes = 1542470366 # from wc -c ckpt.pt\n",
    "print(f\"measured with wc -c ckpt.pt: {measured_bytes}\")\n",
    "print(f\"fluff ratio: {measured_bytes/params_and_buffers_bytes*100:.2f}%\")"
   ]
  },
  {
   "attachments": {},
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "我们还可以估计由AdamW优化器内的权重和缓冲区占据的GPU内存的比率。\n",
    "\n",
    "\n",
    "\n",
    "\n",
    "\n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "memory ratio taken up just for parameters: 3.73%\n"
     ]
    }
   ],
   "source": [
    "gpu_memory = 40e9 # 40 GB A100 GPU, roughly\n",
    "print(f\"memory ratio taken up just for parameters: {params_and_buffers_bytes / gpu_memory * 100:.2f}%\")"
   ]
  },
  {
   "attachments": {},
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "也就是说，对于这个小型模型，内存中并没有太多用于存储权重和AdamW优化器内部的缓冲区，大部分内存用于激活（前向和后向）。当然，对于更大的模型，情况会发生显著变化。"
   ]
  },
  {
   "attachments": {},
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "让我们估算一下单次前向传递的浮点运算次数。"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "name                 flops          ratio (%) \n",
      "attention/kqv            3623878656     1.2426\n",
      "attention/scores         1610612736     0.5522\n",
      "attention/reduce         1610612736     0.5522\n",
      "attention/proj           1207959552     0.4142\n",
      "attention                8053063680     2.7612\n",
      "mlp/ffw1                 4831838208     1.6567\n",
      "mlp/ffw2                 4831838208     1.6567\n",
      "mlp                      9663676416     3.3135\n",
      "block                   17716740096     6.0747\n",
      "transformer            212600881152    72.8963\n",
      "dense                   79047426048    27.1037\n",
      "forward_total          291648307200   100.0000\n",
      "backward_total         583296614400   200.0000\n",
      "total                  874944921600   300.0000\n"
     ]
    }
   ],
   "source": [
    "def flops():\n",
    "    # we only count Weight FLOPs, all other layers (LayerNorm, Softmax, etc) are effectively irrelevant\n",
    "    # we count actual FLOPs, not MACs. Hence 2* all over the place\n",
    "    # basically for any matrix multiply A (BxC) @ B (CxD) -> (BxD) flops are 2*B*C*D\n",
    "\n",
    "    out = OrderedDict()\n",
    "    head_size = n_embd // n_head\n",
    "\n",
    "    # attention blocks\n",
    "    # 1) the projection to key, query, values\n",
    "    out['attention/kqv'] = 2 * block_size * (n_embd * 3*n_embd)\n",
    "    # 2) calculating the attention scores\n",
    "    out['attention/scores'] = 2 * block_size * block_size * n_embd\n",
    "    # 3) the reduction of the values (B, nh, T, T) x (B, nh, T, hs) -> (B, nh, T, hs)\n",
    "    out['attention/reduce'] = 2 * n_head * (block_size * block_size * head_size)\n",
    "    # 4) the final linear projection\n",
    "    out['attention/proj'] = 2 * block_size * (n_embd * n_embd)\n",
    "    out['attention'] = sum(out['attention/'+k] for k in ['kqv', 'scores', 'reduce', 'proj'])\n",
    "\n",
    "    # MLP blocks\n",
    "    ffw_size = 4*n_embd # feed forward size\n",
    "    out['mlp/ffw1'] = 2 * block_size * (n_embd * ffw_size)\n",
    "    out['mlp/ffw2'] = 2 * block_size * (ffw_size * n_embd)\n",
    "    out['mlp'] = out['mlp/ffw1'] + out['mlp/ffw2']\n",
    "\n",
    "    # the transformer and the rest of it\n",
    "    out['block'] = out['attention'] + out['mlp']\n",
    "    out['transformer'] = n_layer * out['block']\n",
    "    out['dense'] = 2 * block_size * (n_embd * vocab_size)\n",
    "\n",
    "    # forward,backward,total\n",
    "    out['forward_total'] = out['transformer'] + out['dense']\n",
    "    out['backward_total'] = 2 * out['forward_total'] # use common estimate of bwd = 2*fwd\n",
    "    out['total'] = out['forward_total'] + out['backward_total']\n",
    "\n",
    "    return out\n",
    "    \n",
    "# compare our param count to that reported by PyTorch\n",
    "f = flops()\n",
    "flops_total = f['forward_total']\n",
    "print(f\"{'name':20s} {'flops':14s} {'ratio (%)':10s}\")\n",
    "for k,v in f.items():\n",
    "    print(f\"{k:20s} {v:14d} {v/flops_total*100:10.4f}\")\n",
    "    "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 9,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "palm_flops: 875062886400, flops: 874944921600, ratio: 1.0001\n"
     ]
    }
   ],
   "source": [
    "# now here is an estimate copy pasted from the PaLM paper\n",
    "# this formula is often used to calculate MFU (model flops utilization)\n",
    "def palm_flops():\n",
    "    \"\"\"estimate of the model flops following PaLM paper formula\"\"\"\n",
    "    # non-embedding model parameters. note that we do not subtract the\n",
    "    # embedding/token params because those are tied and get used in the last layer.\n",
    "    N = params()['total'] - params()['emebedding/position']\n",
    "    L, H, Q, T = n_layer, n_head, n_embd//n_head, block_size\n",
    "    mf_per_token = 6*N + 12*L*H*Q*T\n",
    "    mf = mf_per_token * block_size\n",
    "    return mf\n",
    "\n",
    "print(f\"palm_flops: {palm_flops():d}, flops: {flops()['total']:d}, ratio: {palm_flops()/flops()['total']:.4f}\")"
   ]
  },
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   "attachments": {},
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   "metadata": {},
   "source": [
    "好的，它们非常相似，这让我对我的flops()函数中的数学运算感到相当有信心。现在，A100在张量核上的bfloat16性能被引用为312TFLOPS。那么我们的模型浮点运算次数利用率（MFU）是多少呢？我使用批量大小为20和渐变累积(grad_accum)为5来训练上述模型，在单个A100 GPU上运行时间约为755毫秒。我们得到："
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 10,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "fraction of A100 used: 37.14%\n"
     ]
    }
   ],
   "source": [
    "# here is what we currently roughly measure\n",
    "batch_size = 20 * 5 # 5 is grad_accum, so total batch size is 100\n",
    "measured_time = 0.755 # in seconds per iteration\n",
    "measured_throughput = batch_size / measured_time\n",
    "flops_achieved = f['total'] * measured_throughput\n",
    "\n",
    "# A100 is cited to be 312 TFLOPS of bloat16 running on tensor cores\n",
    "a100_flops_promised = 312e12\n",
    "\n",
    "# the fraction of the A100 that we are using:\n",
    "print(f\"fraction of A100 used: {flops_achieved / a100_flops_promised * 100:.2f}%\")"
   ]
  },
  {
   "attachments": {},
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "供参考，我们希望浮点运算次数利用率（MFU）在50%以上，而且不仅仅是单个GPU，而是整个分布式数据并行（DDP）运行。所以我们仍然有一些工作要做，但至少我们已经接近这个GPU可以实现的目标的两倍左右。"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 11,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "time needed to train the model: 3.46 days\n"
     ]
    }
   ],
   "source": [
    "# Finally let's check out the 6ND approximation as total cost of training in FLOPs\n",
    "model_size = params()['total'] # this is number of parameters, N\n",
    "tokens_num = 300e9 # 300B tokens, this is dataset size in tokens, D\n",
    "a100_flops = 312e12 # 312 TFLOPS\n",
    "assumed_mfu = 0.3 # assume this model flops utilization (take the current 37% from above and add some DDP overhead)\n",
    "flops_throughput = a100_flops * 8 * assumed_mfu # assume an 8XA100 node at 30% utilization\n",
    "flops_needed = 6 * model_size * tokens_num # 6ND\n",
    "time_needed_s = flops_needed / flops_throughput # in seconds\n",
    "print(f\"time needed to train the model: {time_needed_s/3600/24:.2f} days\")"
   ]
  },
  {
   "attachments": {},
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "这是一个相当不错的估算。我训练了这个模型，它大约在4天内收敛。顺便说一下，关于6ND的来源以及一些相关直觉，我推荐[Dzmitry的文章](https://medium.com/@dzmitrybahdanau/the-flops-calculus-of-language-model-training-3b19c1f025e4)。"
   ]
  },
  {
   "attachments": {},
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "现在，浮点运算次数只是一个限制条件，另一个我们必须密切关注的是内存带宽。稍后我们需要估算一下我们模型的加载/存储成本。"
   ]
  }
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