Given a binary search tree, write a function kthSmallest to find the kth smallest element in it.
Note:
- You may assume k is always valid, 1 ≤ k ≤ BST's total elements.
Example 1
Input: root = [3,1,4,null,2], k = 1
3
/ \
1 4
\
2
Output: 1
Example 2
Input: root = [5,3,6,2,4,null,null,1], k = 3
5
/ \
3 6
/ \
2 4
/
1
Output: 3
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int kthSmallest(TreeNode root, int k) {
Stack<TreeNode> stack=new Stack<>();
TreeNode curr=root;
while(curr!=null || !stack.isEmpty()){
while(curr!=null){
stack.push(curr);
curr=curr.left;
}
if(--k!=0)
curr=stack.pop();
else
return stack.pop().val;
curr=curr.right;
}
return 0;
}
}