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patch_strings_in_file
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patch_strings_in_file
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#!/usr/bin/env bash
# Function to replace content in a binary file
# see https://everydaywithlinux.blogspot.com/2012/11/patch-strings-in-binary-files-with-sed.html
function patch_strings_in_file() {
local FILE="$1"
local PATTERN="$2"
local REPLACEMENT="$3"
# Find all unique strings in FILE that contain the pattern
STRINGS=$(strings ${FILE} | grep ${PATTERN} | sort -u -r)
if [ "${STRINGS}" != "" ]; then
echo "File '${FILE}' contain strings with '${PATTERN}' in them:"
for OLD_STRING in ${STRINGS}; do
# Create the new string with a simple bash-replacement
NEW_STRING=${OLD_STRING//${PATTERN}/${REPLACEMENT}}
# Create null terminated ASCII HEX representations of the strings
OLD_STRING_HEX="$(echo -n ${OLD_STRING} | xxd -g 0 -u -ps -c 256)00"
NEW_STRING_HEX="$(echo -n ${NEW_STRING} | xxd -g 0 -u -ps -c 256)00"
if [ ${#NEW_STRING_HEX} -le ${#OLD_STRING_HEX} ]; then
# Pad the replacement string with null terminations so the
# length matches the original string
while [ ${#NEW_STRING_HEX} -lt ${#OLD_STRING_HEX} ]; do
NEW_STRING_HEX="${NEW_STRING_HEX}00"
done
# Now, replace every occurrence of OLD_STRING with NEW_STRING
echo -n "Replacing ${OLD_STRING} with ${NEW_STRING}... "
hexdump -ve '1/1 "%.2X"' ${FILE} \
| sed "s/${OLD_STRING_HEX}/${NEW_STRING_HEX}/g" \
| xxd -r -p >${FILE}.tmp
chmod --reference ${FILE} ${FILE}.tmp
mv ${FILE}.tmp ${FILE}
echo "Done!"
else
echo "New string '${NEW_STRING}' is longer than old" \
"string '${OLD_STRING}'. Skipping."
fi
done
fi
}
patch_strings_in_file "$1" "$2" "$3"