快速排序也采用了分治的思想:把原始的数组筛选成较小和较大的两个子数组,然后递归地排序两个子数组。
快速排序算法模板:
void quickSort(int[] nums, int left, int high) {
if (left >= high) {
return;
}
int i = left - 1, j = high + 1;
int x = nums[left];
while (i < j) {
while (nums[++i] < x);
while (nums[--j] > x);
if (i < j) {
int t = nums[i];
nums[i] = nums[j];
nums[j] = t;
}
}
quickSort(nums, left, j);
quickSort(nums, j + 1, high);
}
给定你一个长度为 n
的整数数列。
请你使用快速排序对这个数列按照从小到大进行排序。
并将排好序的数列按顺序输出。
输入格式
输入共两行,第一行包含整数 n。
第二行包含 n 个整数(所有整数均在 1∼10^9 范围内),表示整个数列。
输出格式
输出共一行,包含 n 个整数,表示排好序的数列。
数据范围
1≤n≤100000
输入样例:
5
3 1 2 4 5
输出样例:
1 2 3 4 5
N = int(input())
nums = list(map(int, input().split()))
def quick_sort(nums, left, high):
if left >= high:
return
i, j = left - 1, high + 1
x = nums[(left + high) >> 1]
while i < j:
while 1:
i += 1
if nums[i] >= x:
break
while 1:
j -= 1
if nums[j] <= x:
break
if i < j:
nums[i], nums[j] = nums[j], nums[i]
quick_sort(nums, left, j)
quick_sort(nums, j + 1, high)
quick_sort(nums, 0, N - 1)
print(' '.join(list(map(str, nums))))
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int[] nums = new int[n];
for (int i = 0; i < n; ++i) {
nums[i] = sc.nextInt();
}
quickSort(nums, 0, n - 1);
for (int i = 0; i < n; ++i) {
System.out.printf("%d ", nums[i]);
}
}
public static void quickSort(int[] nums, int left, int high) {
if (left >= high) {
return;
}
int i = left - 1, j = high + 1;
int x = nums[left];
while (i < j) {
while (nums[++i] < x);
while (nums[--j] > x);
if (i < j) {
int t = nums[i];
nums[i] = nums[j];
nums[j] = t;
}
}
quickSort(nums, left, j);
quickSort(nums, j + 1, high);
}
}
var buf = '';
process.stdin.on('readable', function () {
var chunk = process.stdin.read();
if (chunk) buf += chunk.toString();
});
let getInputArgs = line => {
return line.split(' ').filter(s => s !== '').map(x => parseInt(x));
}
function quickSort(nums, left, high) {
if (left >= high) {
return;
}
let i = left - 1;
let j = high + 1;
let x = nums[(left + high) >> 1];
while (i < j) {
while (nums[++i] < x);
while (nums[--j] > x);
if (i < j) {
const t = nums[i];
nums[i] = nums[j];
nums[j] = t;
}
}
quickSort(nums, left, j);
quickSort(nums, j + 1, high);
}
process.stdin.on('end', function () {
buf.split('\n').forEach(function (line, lineIdx) {
if (lineIdx % 2 === 1) {
nums = getInputArgs(line);
quickSort(nums, 0, nums.length - 1);
console.log(nums.join(' '));
}
});
});
package main
import "fmt"
func quickSort(nums []int, left, high int) {
if left >= high {
return
}
i, j := left-1, high+1
x := nums[(left+high)>>1]
for i < j {
for {
i++
if nums[i] >= x {
break
}
}
for {
j--
if nums[j] <= x {
break
}
}
if i < j {
nums[i], nums[j] = nums[j], nums[i]
}
}
quickSort(nums, left, j)
quickSort(nums, j+1, high)
}
func main() {
var n int
fmt.Scanf("%d\n", &n)
nums := make([]int, n)
for i := 0; i < n; i++ {
fmt.Scanf("%d", &nums[i])
}
quickSort(nums, 0, n-1)
for _, v := range nums {
fmt.Printf("%d ", v)
}
}