We read every piece of feedback, and take your input very seriously.
To see all available qualifiers, see our documentation.
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
Hi The site I am scraping has urls like:
http://remote.com/i-love-cats/1 http://remote.com/dogs-are-really-great/2 http://remote.com/pupies_kanGourOUs/3
I want to match them with local urls like those:
http://localhost:5000/1 http://localhost:5000/2 http://localhost:5000/3
Is there some magical way to do it?
Or I need to do like #107 and also add custom code in an external two-column db table to match
1 => http://remote.com/i-love-cats/1 ...
Sure as an alternate solution I could maybe add a route like @api.route('page/{complete_remote_url}', '{complete_remote_url}') and do like :
@api.route('page/{complete_remote_url}', '{complete_remote_url}')
wget http://localhost:5000/page/http://remote.com/i-love-cats/1
but I want to hide the scraped site url so the caller does not see the url
The text was updated successfully, but these errors were encountered:
No branches or pull requests
Hi
The site I am scraping has urls like:
I want to match them with local urls like those:
Is there some magical way to do it?
Or I need to do like #107 and also
add custom code in an external two-column db table to match
Sure as an alternate solution I could maybe add a route like
@api.route('page/{complete_remote_url}', '{complete_remote_url}')
and do like :
but I want to hide the scraped site url so the caller does not see the url
The text was updated successfully, but these errors were encountered: