Specify only one channel #8
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fcakyon
ale94mleon
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Hi, I am using this action and so far so good. However, a new conda-recipe that I am creating has really nasty dependencies and only works if |
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Answered by
fcakyon
Nov 4, 2022
Replies: 2 comments
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You may have to create a fork, update this line and use that as your action 👍 conda-publish-action/entrypoint.sh Line 28 in 02852ad |
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You may have to create a fork, update this line and use that as your action 👍
conda-publish-action/entrypoint.sh
Line 28 in 02852ad