How the Search Tree branches in routing solver? #4409
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it does not branch. Local search is implemented inside the tree search with hacks. |
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not exactly. As far as I remember, the solver builds a balanced binary
search tree where each leaf is a solution.
Branches should be the number of branches explored in the balanced search
tree.
But just ignore it, it is irrelevant. They are just a tool used to
implement the LS.
Laurent Perron | Operations Research | ***@***.*** | (33) 1 42 68 53
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Le jeu. 10 oct. 2024 à 15:19, FirstPotatoOnMars ***@***.***>
a écrit :
… Thanks a lot for answering me!
I still have the following question: what is each of the *branches* of
search tree means? Is each one a solution?
Because I notice that the value of *branches* and *neighbors* grows with
the solving process. What is the difference between *branches* and
*neighbors*? What exactly do these two referring to?
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Hi, I am really interested in the search tree of the routing solver. I know that in exact algorithms, the branch and bound works based on a search tree and can branch on variables or constraints.
And my question is how search tree works in this routing solver, and how it branches? As I know the algorithm of the routing solver is mainly based on meta-heuristics (if I understand the solver right)? I would be very grateful if someone can help me answer this !
Start search (memory used = 205.35 MB)
Root node processed (time = 0 ms, constraints = 197, memory used = 205.35 MB)
Solution #0 (261798, time = 0 ms, branches = 0, failures = 0, depth = 0, memory used = 205.35 MB)
Finished search tree (time = 0 ms, branches = 0, failures = 1, memory used = 205.35 MB)
End search (time = 1 ms, branches = 0, failures = 1, memory used = 205.35 MB, speed = 0 branches/s)
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