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Copy path13. Remove K Digits.cpp
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13. Remove K Digits.cpp
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/*
Given a non-negative integer num represented as a string, remove k digits from the number so that the new number is the smallest possible.
Note:
The length of num is less than 10002 and will be ≥ k.
The given num does not contain any leading zero.
Example 1:
Input: num = "1432219", k = 3
Output: "1219"
Explanation: Remove the three digits 4, 3, and 2 to form the new number 1219 which is the smallest.
Example 2:
Input: num = "10200", k = 1
Output: "200"
Explanation: Remove the leading 1 and the number is 200. Note that the output must not contain leading zeroes.
Example 3:
Input: num = "10", k = 2
Output: "0"
Explanation: Remove all the digits from the number and it is left with nothing which is 0.
*/
class Solution {
public:
string removeKdigits(string num, int k)
{
int n=num.size();
if(k>=n) return "0";
int i=0;
while( (i<num.size()-1) && (k>0) )
{
if(num[i]>num[i+1])
{
num.erase(i, 1);
k--;
if(i!=0)
i--;
}
else
i++;
}
//if we have traversed the string and still k>0, that means there are repeated same digits
//Ex: "1111111" . So we remove k digits from end.
if(k!=0)
{
int l = num.size()-k;
num.erase(num.begin()+l, num.end());
}
//removing leading zeros if any
for(int i=0;i<num.size();i++)
{
if(num[i]!='0')
return num.substr(i);
}
return "0";
}
};