Add support for deriving ToExpr from Show
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I didn't really change the `ToExpr` class, but this adds two useful functions that allow one to implement a `ToExpr` instance if a type already has a `Show` instance.
phadej
reviewed
Aug 31, 2024
| -} | ||
| showToExpr :: Show a => a -> Either ShowParseFailed Expr | ||
| showToExpr a = | ||
| case Parsec.parse exprParser "" (show a) of |
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This doesn't work. exprParser is not parser for Haskell expressions. Close syntax, but not the same.
EDIT: In particular infix operators are something which is not accepted by exprParser.
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I didn't really change the
ToExprclass, but this adds two useful functions that allow one to implement aToExprinstance if a type already has aShowinstance.