forked from fishercoder1534/Leetcode
-
Notifications
You must be signed in to change notification settings - Fork 1
/
_888.java
67 lines (64 loc) · 1.82 KB
/
_888.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
package com.fishercoder.solutions;
import java.util.HashSet;
/**
* 888. Fair Candy Swap
*
* Alice and Bob have candy bars of different sizes: A[i] is the size of the i-th bar of candy that Alice has, and B[j]
* is the size of the j-th bar of candy that Bob has.
*
* Since they are friends, they would like to exchange one candy bar each so that after the exchange, they both have the
* same total amount of candy. (The total amount of candy a person has is the sum of the sizes of candy bars they have.)
*
* Return an integer array ans where ans[0] is the size of the candy bar that Alice must exchange, and ans[1] is the
* size of the candy bar that Bob must exchange.
*
* If there are multiple answers, you may return any one of them. It is guaranteed an answer exists.
*
*
*
* Example 1:
*
* Input: A = [1,1], B = [2,2]
* Output: [1,2]
* Example 2:
*
* Input: A = [1,2], B = [2,3]
* Output: [1,2]
* Example 3:
*
* Input: A = [2], B = [1,3]
* Output: [2,3]
* Example 4:
*
* Input: A = [1,2,5], B = [2,4]
* Output: [5,4]
*/
public class _888 {
public static class Solution1 {
public int[] fairCandySwap(int[] A, int[] B) {
int aSum = 0;
int bSum = 0;
int diff = 0;
int[] ans = new int[2];
for (int bar : A) {
aSum += bar;
}
for (int bar : B) {
bSum += bar;
}
diff = aSum - bSum;
HashSet<Integer> set = new HashSet<>();
for (int bar : A) {
set.add(bar);
}
for (int bar : B) {
if (set.contains(bar + diff / 2)) {
ans[0] = bar + diff / 2;
ans[1] = bar;
break;
}
}
return ans;
}
}
}