(a) Learn C
Followed by C++, C# and Java
(infinite times)
(b) 100
(c) 3.140000
(d) Error.
(a) Semicolor missing in the declaration of a function.
A function cannot return more than one values.
(b) message function has return type void, so it cannot be assigned to any variable.
(c) Function definition argument should have a datatype.
Function is not defined before calling, or there should be prototype declaration of the function.
(d) Invalid use of a semicolon.
(e) Function definition is invalid in other functions.
(f) void is send in the message as argument, which is invalid.
(a) No! There is an Invalid use of a semicolon.
(b)
(1) False.
(2) False.
(3) True.
(4) False.
(5) True.
(6) True.
(7) True.
(8) False.
(9) True.
(10) False.
(a)
#include<stdio.h>
int fact(int );
int main()
{
int num,fac;
scanf("%d",&num);
fac=fact(num);
printf("%d",fac);
return 0;
}
int fact(int n)
{
int i,factorial=1;
for(i=1;i<=n;i++)
{
factorial*=i;
}
return factorial;
}
(b)
#include<stdio.h>
#include<math.h>
int power(int,int);
int main()
{
int a,b,ans;
scanf("%d %d",&a,&b);
ans=power(a,b);
printf("%d",ans);
return 0;
}
int power(int a,int b)
{
int d;
d=pow(a,b);
return d;
}
OR
#include<stdio.h>
#include<math.h>
int power(int,int);
int main()
{
int a,b,ans;
scanf("%d %d",&a,&b);
ans=power(a,b);
printf("%d",ans);
return 0;
}
int power(int x, int y)
{
int num = 1, i;
for (i = 1; i <= y; i++)
num = num*x;
return(num);
}
(c)
#include<stdio.h>
#include<conio.h>
void rom(int);
void print(int, char);
int main()
{
int yer;
printf("Enter the year : ");
scanf("%d", &yer);
printf("\nRoman equivalent of %d is : ", yer);
rom(yer);
getch();
return 0;
}
void rom(int yer)
{
int v, x, l, c, d, m;
m = yer / 1000;
print(m, 'm');
yer %= 1000;
d = yer / 500;
print(d, 'd');
yer %= 500;
c = yer / 100;
print(c, 'c');
yer %= 100;
l = yer / 50;
print(l, 'l');
yer %= 50;
x = yer / 10;
print(x, 'x');
yer %= 10;
v = yer / 5;
print(v, 'v');
yer %= 5;
print(yer, 'i');
}
void print(int a, char c)
{
int i;
for (i = 0; i < a; i++)
printf("%c", c);
}
(d)
#include<stdio.h>
int calc(int );
int main()
{
int year,leap;
printf("Enter year = ");
scanf("%d",&year);
leap=calc(year);
if(leap==1)
printf("%d is leap year",year);
else
printf("%d is not a leap year",year);
return 0;
}
int calc(int year)
{
if(yr % 4 == 0 && (yr % 100 != 0 || yr % 400 == 0))
return 1;
else
return 0;
}
(e)
#include<stdio.h>
void prime(int );
int main()
{
int num;
printf("Enter a number = ");
scanf("%d",&num);
prime(num);
return(0);
}
void prime(int n)
{
int i,j,isPrime=1;
for(i=2;i<=n;i++)
{
if(n%i==0)
{
isPrime=1;
for(j=2;j<=i/2;j++)
{
if(i%j==0)
{
isPrime=0;
break;
}
}
if(isPrime==1)
printf("%d\n",i);
}
}
return 0;
}
OR
#include<stdio.h>
#include<conio.h>
int check_prime(int);
void pf(int);
int main()
{
int num;
printf("Enter a number : ");
scanf("%d", &num);
pf(num);
_getch();
return 0;
}
void pf(int num)
{
int i;
for (i = 2; num != 1; i++) //loop for obtaining the numbers.
{
if (num%i != 0)// If the number is not a factor
continue;
else
{
//If the number is prime, so check if it is prime
if(check_prime(i) == 1)
{
while (num%i == 0)
{
printf("%d, ", i);
num /= i;
}
}
}
}
}
//returns 1 if prime, otherwise 0.
int check_prime(int num)
{
int i = 2;
while(i < num)
{
if(i%num == 0)
return 0;
i++;
}
if(i == num)
return 1;
}