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left++根本不可能执行,因为要执行left++必须left停留在<mid的元素上,也就是说退出循环left++的循环,只能是left==right,那这时left的位置的元素已经是>mid的了
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left++根本不可能执行,因为要执行left++必须left停留在<mid的元素上,也就是说退出循环left++的循环,只能是left==right,那这时left的位置的元素已经是>mid的了
The text was updated successfully, but these errors were encountered: