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請見附檔 新增了Pattern 這個物件 Pattern 有 similar() 和 getSimilar() 這兩個函數 如果直接將相同物件getSimilar() 的回傳值給similar(),會造成exception pattern:similar(pattern:getSimilar()) GET LUA VARIABLE 'V1' 會不正常 如果將此行拿掉則會正常
另外,間接設定similar 則會正常 sim = pattern:getSimilar() pattern:similar(sim)
problem.zip
The text was updated successfully, but these errors were encountered:
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請見附檔
新增了Pattern 這個物件
Pattern 有 similar() 和 getSimilar() 這兩個函數
如果直接將相同物件getSimilar() 的回傳值給similar(),會造成exception
pattern:similar(pattern:getSimilar())
GET LUA VARIABLE 'V1' 會不正常
如果將此行拿掉則會正常
另外,間接設定similar 則會正常
sim = pattern:getSimilar()
pattern:similar(sim)
problem.zip
The text was updated successfully, but these errors were encountered: