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is misleading because the tokens "t" should include trailing whitespace when appropriate. If you use the built-in tokenizer instead, the tokens include whitespace by default. Also, the normalized "n" should be shown to exclude whitespace so as not to fool the token comparators.
Why is this important? Because if you omit whitespace the segment joining phase will run tokens together like this:
This example from the documentation:
is misleading because the tokens "t" should include trailing whitespace when appropriate. If you use the built-in tokenizer instead, the tokens include whitespace by default. Also, the normalized "n" should be shown to exclude whitespace so as not to fool the token comparators.
Why is this important? Because if you omit whitespace the segment joining phase will run tokens together like this:
N.B. This output was generated from the slighly modified (to exercise the segment joiner) input:
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