From 2bbc3dcd924c693ef3e593a6712960965bd88f83 Mon Sep 17 00:00:00 2001 From: Jander Date: Thu, 27 Jun 2024 14:08:27 -0300 Subject: [PATCH] =?UTF-8?q?Publica=C3=A7=C3=A3o=20autom=C3=A1tica?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- cap-pratica-algoritmos/index.html | 114 -------------- ...oritmos_programacao-pratica-algoritmos.pdf | Bin 405740 -> 406565 bytes .../pratica-algoritmos-listagem-geral.html | 115 +-------------- ...problemas-complementares-condicionais.html | 114 -------------- ...ritmos-problemas-condicionais-simples.html | 114 -------------- ...os-problemas-repeticoes-identificacao.html | 114 -------------- ...tmos-problemas-repeticoes-progressoes.html | 114 -------------- ...goritmos-problemas-repeticoes-simples.html | 114 -------------- ...oritmos-problemas-repeticoes-variados.html | 139 ++++-------------- ...ica-algoritmos-respostas-condicionais.html | 114 -------------- ...atica-algoritmos-respostas-repeticoes.html | 114 -------------- ...preambulo_prefacio_pratica_algoritmos.html | 114 -------------- cap-pratica-algoritmos/search.json | 4 +- 13 files changed, 28 insertions(+), 1256 deletions(-) diff --git a/cap-pratica-algoritmos/index.html b/cap-pratica-algoritmos/index.html index 68e4c20..5290d6f 100644 --- a/cap-pratica-algoritmos/index.html +++ b/cap-pratica-algoritmos/index.html @@ -453,120 +453,6 @@

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Problema B.8

  • #0067: Problema B.10
  • #0068: Problema 6.3
    • +
  • #0069: Problema 5.12

    • @@ -426,120 +427,6 @@

    2) { - container.appendChild(note.children[0].cloneNode(true)); - for (let i = 1; i < note.children.length; i++) { - const child = note.children[i]; - if (child.tagName === "P" && child.innerText === "") { - continue; - } else { - container.appendChild(child.cloneNode(true)); - break; - } - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(container); - } - return container.innerHTML - } else { - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } else { - // Remove any anchor links if they are present - const anchorLink = note.querySelector('a.anchorjs-link'); - if (anchorLink) { - anchorLink.remove(); - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } - for (var i=0; i res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.getElementById(id); - if (note !== null) { - const html = processXRef(id, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - } else { - // See if we can fetch a full url (with no hash to target) - // This is a special case and we should probably do some content thinning / targeting - fetch(url) - .then(res => res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.querySelector('main.content'); - if (note !== null) { - // This should only happen for chapter cross references - // (since there is no id in the URL) - // remove the first header - if (note.children.length > 0 && note.children[0].tagName === "HEADER") { - note.children[0].remove(); - } - const html = processXRef(null, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - }, function(instance) { - }); } let selectedAnnoteEl; const selectorForAnnotation = ( cell, annotation) => { diff --git a/cap-pratica-algoritmos/pratica-algoritmos-problemas-complementares-condicionais.html b/cap-pratica-algoritmos/pratica-algoritmos-problemas-complementares-condicionais.html index afc8e4a..517583f 100644 --- a/cap-pratica-algoritmos/pratica-algoritmos-problemas-complementares-condicionais.html +++ b/cap-pratica-algoritmos/pratica-algoritmos-problemas-complementares-condicionais.html @@ -595,120 +595,6 @@

    2) { - container.appendChild(note.children[0].cloneNode(true)); - for (let i = 1; i < note.children.length; i++) { - const child = note.children[i]; - if (child.tagName === "P" && child.innerText === "") { - continue; - } else { - container.appendChild(child.cloneNode(true)); - break; - } - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(container); - } - return container.innerHTML - } else { - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } else { - // Remove any anchor links if they are present - const anchorLink = note.querySelector('a.anchorjs-link'); - if (anchorLink) { - anchorLink.remove(); - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } - for (var i=0; i res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.getElementById(id); - if (note !== null) { - const html = processXRef(id, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - } else { - // See if we can fetch a full url (with no hash to target) - // This is a special case and we should probably do some content thinning / targeting - fetch(url) - .then(res => res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.querySelector('main.content'); - if (note !== null) { - // This should only happen for chapter cross references - // (since there is no id in the URL) - // remove the first header - if (note.children.length > 0 && note.children[0].tagName === "HEADER") { - note.children[0].remove(); - } - const html = processXRef(null, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - }, function(instance) { - }); } let selectedAnnoteEl; const selectorForAnnotation = ( cell, annotation) => { diff --git a/cap-pratica-algoritmos/pratica-algoritmos-problemas-condicionais-simples.html b/cap-pratica-algoritmos/pratica-algoritmos-problemas-condicionais-simples.html index 2b7bfd7..337e219 100644 --- a/cap-pratica-algoritmos/pratica-algoritmos-problemas-condicionais-simples.html +++ b/cap-pratica-algoritmos/pratica-algoritmos-problemas-condicionais-simples.html @@ -747,120 +747,6 @@

    { - // Strip column container classes - const stripColumnClz = (el) => { - el.classList.remove("page-full", "page-columns"); - if (el.children) { - for (const child of el.children) { - stripColumnClz(child); - } - } - } - stripColumnClz(note) - if (id === null || id.startsWith('sec-')) { - // Special case sections, only their first couple elements - const container = document.createElement("div"); - if (note.children && note.children.length > 2) { - container.appendChild(note.children[0].cloneNode(true)); - for (let i = 1; i < note.children.length; i++) { - const child = note.children[i]; - if (child.tagName === "P" && child.innerText === "") { - continue; - } else { - container.appendChild(child.cloneNode(true)); - break; - } - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(container); - } - return container.innerHTML - } else { - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } else { - // Remove any anchor links if they are present - const anchorLink = note.querySelector('a.anchorjs-link'); - if (anchorLink) { - anchorLink.remove(); - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } - for (var i=0; i res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.getElementById(id); - if (note !== null) { - const html = processXRef(id, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - } else { - // See if we can fetch a full url (with no hash to target) - // This is a special case and we should probably do some content thinning / targeting - fetch(url) - .then(res => res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.querySelector('main.content'); - if (note !== null) { - // This should only happen for chapter cross references - // (since there is no id in the URL) - // remove the first header - if (note.children.length > 0 && note.children[0].tagName === "HEADER") { - note.children[0].remove(); - } - const html = processXRef(null, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - }, function(instance) { - }); } let selectedAnnoteEl; const selectorForAnnotation = ( cell, annotation) => { diff --git a/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-identificacao.html b/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-identificacao.html index 3331df9..b29711c 100644 --- a/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-identificacao.html +++ b/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-identificacao.html @@ -601,120 +601,6 @@

    2) { - container.appendChild(note.children[0].cloneNode(true)); - for (let i = 1; i < note.children.length; i++) { - const child = note.children[i]; - if (child.tagName === "P" && child.innerText === "") { - continue; - } else { - container.appendChild(child.cloneNode(true)); - break; - } - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(container); - } - return container.innerHTML - } else { - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } else { - // Remove any anchor links if they are present - const anchorLink = note.querySelector('a.anchorjs-link'); - if (anchorLink) { - anchorLink.remove(); - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } - for (var i=0; i res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.getElementById(id); - if (note !== null) { - const html = processXRef(id, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - } else { - // See if we can fetch a full url (with no hash to target) - // This is a special case and we should probably do some content thinning / targeting - fetch(url) - .then(res => res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.querySelector('main.content'); - if (note !== null) { - // This should only happen for chapter cross references - // (since there is no id in the URL) - // remove the first header - if (note.children.length > 0 && note.children[0].tagName === "HEADER") { - note.children[0].remove(); - } - const html = processXRef(null, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - }, function(instance) { - }); } let selectedAnnoteEl; const selectorForAnnotation = ( cell, annotation) => { diff --git a/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-progressoes.html b/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-progressoes.html index b26891c..8612972 100644 --- a/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-progressoes.html +++ b/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-progressoes.html @@ -458,120 +458,6 @@

    2) { - container.appendChild(note.children[0].cloneNode(true)); - for (let i = 1; i < note.children.length; i++) { - const child = note.children[i]; - if (child.tagName === "P" && child.innerText === "") { - continue; - } else { - container.appendChild(child.cloneNode(true)); - break; - } - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(container); - } - return container.innerHTML - } else { - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } else { - // Remove any anchor links if they are present - const anchorLink = note.querySelector('a.anchorjs-link'); - if (anchorLink) { - anchorLink.remove(); - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } - for (var i=0; i res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.getElementById(id); - if (note !== null) { - const html = processXRef(id, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - } else { - // See if we can fetch a full url (with no hash to target) - // This is a special case and we should probably do some content thinning / targeting - fetch(url) - .then(res => res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.querySelector('main.content'); - if (note !== null) { - // This should only happen for chapter cross references - // (since there is no id in the URL) - // remove the first header - if (note.children.length > 0 && note.children[0].tagName === "HEADER") { - note.children[0].remove(); - } - const html = processXRef(null, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - }, function(instance) { - }); } let selectedAnnoteEl; const selectorForAnnotation = ( cell, annotation) => { diff --git a/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-simples.html b/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-simples.html index 77669c3..c1f66d1 100644 --- a/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-simples.html +++ b/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-simples.html @@ -646,120 +646,6 @@

    2) { - container.appendChild(note.children[0].cloneNode(true)); - for (let i = 1; i < note.children.length; i++) { - const child = note.children[i]; - if (child.tagName === "P" && child.innerText === "") { - continue; - } else { - container.appendChild(child.cloneNode(true)); - break; - } - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(container); - } - return container.innerHTML - } else { - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } else { - // Remove any anchor links if they are present - const anchorLink = note.querySelector('a.anchorjs-link'); - if (anchorLink) { - anchorLink.remove(); - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } - for (var i=0; i res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.getElementById(id); - if (note !== null) { - const html = processXRef(id, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - } else { - // See if we can fetch a full url (with no hash to target) - // This is a special case and we should probably do some content thinning / targeting - fetch(url) - .then(res => res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.querySelector('main.content'); - if (note !== null) { - // This should only happen for chapter cross references - // (since there is no id in the URL) - // remove the first header - if (note.children.length > 0 && note.children[0].tagName === "HEADER") { - note.children[0].remove(); - } - const html = processXRef(null, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - }, function(instance) { - }); } let selectedAnnoteEl; const selectorForAnnotation = ( cell, annotation) => { diff --git a/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-variados.html b/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-variados.html index bb160ef..85fde10 100644 --- a/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-variados.html +++ b/cap-pratica-algoritmos/pratica-algoritmos-problemas-repeticoes-variados.html @@ -620,6 +620,31 @@

    +
    +
    +
    + +
    +
    +Problema 5.12 [#0069] +
    +
    +
    +
    +

    Um número inteiro é comummente escrito na base 10. Assim, o número \(2601\) pode ser entendido como \({1 \times 10^0} + {0 \times 10^1} + {6 \times 10^2} + {2 \times 10^3}\).

    +

    Escreva um algoritmo que decomponha qualquer valor inteiro positivo em suas potências de 10 (começando pelas unidades; \(10^0\)). A solução deve deixar claros os cálculos usados para separar o valor em suas partes relevantes.

    +

    Como exemplo, para 1003, apresentar

    +

    3 x 10^0

    +

    0 x 10^1

    +

    0 x 10^2

    +

    1 x 10^3

    +
    +
    +
    + @@ -739,120 +764,6 @@

    2) { - container.appendChild(note.children[0].cloneNode(true)); - for (let i = 1; i < note.children.length; i++) { - const child = note.children[i]; - if (child.tagName === "P" && child.innerText === "") { - continue; - } else { - container.appendChild(child.cloneNode(true)); - break; - } - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(container); - } - return container.innerHTML - } else { - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } else { - // Remove any anchor links if they are present - const anchorLink = note.querySelector('a.anchorjs-link'); - if (anchorLink) { - anchorLink.remove(); - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } - for (var i=0; i res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.getElementById(id); - if (note !== null) { - const html = processXRef(id, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - } else { - // See if we can fetch a full url (with no hash to target) - // This is a special case and we should probably do some content thinning / targeting - fetch(url) - .then(res => res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.querySelector('main.content'); - if (note !== null) { - // This should only happen for chapter cross references - // (since there is no id in the URL) - // remove the first header - if (note.children.length > 0 && note.children[0].tagName === "HEADER") { - note.children[0].remove(); - } - const html = processXRef(null, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - }, function(instance) { - }); } let selectedAnnoteEl; const selectorForAnnotation = ( cell, annotation) => { diff --git a/cap-pratica-algoritmos/pratica-algoritmos-respostas-condicionais.html b/cap-pratica-algoritmos/pratica-algoritmos-respostas-condicionais.html index 078d919..668797c 100644 --- a/cap-pratica-algoritmos/pratica-algoritmos-respostas-condicionais.html +++ b/cap-pratica-algoritmos/pratica-algoritmos-respostas-condicionais.html @@ -528,120 +528,6 @@

    2) { - container.appendChild(note.children[0].cloneNode(true)); - for (let i = 1; i < note.children.length; i++) { - const child = note.children[i]; - if (child.tagName === "P" && child.innerText === "") { - continue; - } else { - container.appendChild(child.cloneNode(true)); - break; - } - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(container); - } - return container.innerHTML - } else { - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } else { - // Remove any anchor links if they are present - const anchorLink = note.querySelector('a.anchorjs-link'); - if (anchorLink) { - anchorLink.remove(); - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } - for (var i=0; i res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.getElementById(id); - if (note !== null) { - const html = processXRef(id, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - } else { - // See if we can fetch a full url (with no hash to target) - // This is a special case and we should probably do some content thinning / targeting - fetch(url) - .then(res => res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.querySelector('main.content'); - if (note !== null) { - // This should only happen for chapter cross references - // (since there is no id in the URL) - // remove the first header - if (note.children.length > 0 && note.children[0].tagName === "HEADER") { - note.children[0].remove(); - } - const html = processXRef(null, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - }, function(instance) { - }); } let selectedAnnoteEl; const selectorForAnnotation = ( cell, annotation) => { diff --git a/cap-pratica-algoritmos/pratica-algoritmos-respostas-repeticoes.html b/cap-pratica-algoritmos/pratica-algoritmos-respostas-repeticoes.html index 9a92b45..bb246a0 100644 --- a/cap-pratica-algoritmos/pratica-algoritmos-respostas-repeticoes.html +++ b/cap-pratica-algoritmos/pratica-algoritmos-respostas-repeticoes.html @@ -922,120 +922,6 @@

    7  2) { - container.appendChild(note.children[0].cloneNode(true)); - for (let i = 1; i < note.children.length; i++) { - const child = note.children[i]; - if (child.tagName === "P" && child.innerText === "") { - continue; - } else { - container.appendChild(child.cloneNode(true)); - break; - } - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(container); - } - return container.innerHTML - } else { - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } else { - // Remove any anchor links if they are present - const anchorLink = note.querySelector('a.anchorjs-link'); - if (anchorLink) { - anchorLink.remove(); - } - if (window.Quarto?.typesetMath) { - window.Quarto.typesetMath(note); - } - return note.innerHTML; - } - } - for (var i=0; i res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.getElementById(id); - if (note !== null) { - const html = processXRef(id, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - } else { - // See if we can fetch a full url (with no hash to target) - // This is a special case and we should probably do some content thinning / targeting - fetch(url) - .then(res => res.text()) - .then(html => { - const parser = new DOMParser(); - const htmlDoc = parser.parseFromString(html, "text/html"); - const note = htmlDoc.querySelector('main.content'); - if (note !== null) { - // This should only happen for chapter cross references - // (since there is no id in the URL) - // remove the first header - if (note.children.length > 0 && note.children[0].tagName === "HEADER") { - note.children[0].remove(); - } - const html = processXRef(null, note); - instance.setContent(html); - } - }).finally(() => { - instance.enable(); - instance.show(); - }); - } - }, function(instance) { - }); } let selectedAnnoteEl; const selectorForAnnotation = ( cell, annotation) => { diff --git a/cap-pratica-algoritmos/preambulo_prefacio_pratica_algoritmos.html b/cap-pratica-algoritmos/preambulo_prefacio_pratica_algoritmos.html index fe0ca51..2980d9f 100644 --- a/cap-pratica-algoritmos/preambulo_prefacio_pratica_algoritmos.html +++ b/cap-pratica-algoritmos/preambulo_prefacio_pratica_algoritmos.html @@ -369,120 +369,6 @@

    Prefácio

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Embora tenha tenham sido preenchidas todas as vagas, houve uma preocupação grande quanto às categorias Infantil A e Sênior, temendo que não houvesse atletas suficientes para elas.\nEscreva um algoritmo completo para processar a idade de todos os participantes e determinar a quantidade de nadadores pertencentes ao Infantil A e Sênior.\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.2 [#0032]\n\n\n\n\nUm sistema monitora a pressão de uma caldeira registrando uma medida a cada cinco minutos. Como o sistema funciona continuamente, os dados são registrados diariamente, com a primeira medida a 0h e a última às 23h55min.\nEscreva um algoritmo para processar todos os dados colhido em um dia e determinar a a pressão média nesse período.\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.3 [#0033]\n\n\n\n\nÉ preciso processar o resultado de uma pesquisa de opinião para a qual era possível escolher entre sim, não e não sei.\nEscreva um algoritmo para processar uma sequência de respostas (com mínimo de uma resposta) e determinar as porcentagens de cada categoria.\nDica: Represente as comparações usando texto em nível alto de abstração (exemplo: “se a resposta foi sim, então…”).\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.4 [#0034]\n\n\n\n\nUm relatório de gastos é apresentado mensalmente ao gerente de uma empresa. Nesse relatório constam, logo no início, a quantidade de despesas individuais e, seguindo a essa informação, vêm os valores em R$ de cada gasto realizado. Deseja-se saber quantos desses valores são superiores a R$1000,00.\nEscreva um algoritmo para processar os dados descritos e apresentar a quantidade desejada e a porcentagem desta em relação ao número total de gastos realizados.\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.5 [#0035]\n\n\n\n\nA Universidade promoveu um um show de música folclórica em seu Anfiteatro principal, o qual tem capacidade para 400 pessoas. Os ingressos foram grátis e distribuídos com antecedência. Na noite do espetáculo, todos os assentos foram ocupados.\nPara colher informações sobre o público participante, foi perguntado a cada ingressante sua identidade de gênero e sua idade. Os gêneros foram anotados da seguinte forma: 1 - cisgênero; 2 - transgênero e 3 - não binário.\nOs dados de interesse para a análise incluem:\n\nas porcentagens de cada grupo em relação ao total;\nas idades médias de cada grupo.\n\nEscreva um algoritmo para processar uma sequência de informações que consiste, para cada um dos presentes no show, no número referente ao seu grupo e sua idade. O pseudocódigo deve apresentar as porcentagens indicadas e as médias que existirem.\n Comentário 7.2\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.6 [#0036]\n\n\n\n\nEscreva um algoritmo para, a partir de um valor em \\(\\mathbb{Z}^*\\), apresentar todos seus divisores e a soma destes divisores.\n Resposta 7.13\n Comentário 7.3\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.7 [#0037]\n\n\n\n\nConsidere o seguinte problema:\n\nEscreva um algoritmo para processar uma sequência indefinida e não vazia de valores inteiros (todos positivos) e determinar o valor máximo. A sequência é terminada por um valor sentinela igual a -1.\n\nPara esse problema, foi apresentado o seguinte algoritmo:\n\n\n\n\n\nEssa solução, porém, contém um erro de lógica. Identifique-o e proponha a correção.\n Comentário 7.4\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.8 [#0038]\n\n\n\n\nAdson Biardeyson da Gama e Rafaela Xiomara Corocher são investidores.\nAdson tem uma aplicação com valor atual de R$12.000,00. Essa aplicação rende 1,2% de juros ao mês.\nRafaela, por sua vez, tem uma aplicação de R$11.500,00, cujo rendimento mensal é de 1,9%.\nEscreva um algoritmo que apresente a evolução simultânea dos saldos de ambas as aplicações mês a mês (incluindo o mês inicial), até que a aplicação de Rafaela supere a de Adson. O número de meses decorridos até esta situação deve também ser apresentado.\nPara referência, o algoritmo deveria produzir um resultado como o seguinte:\n 12000.00 11500.00\n 12144.00 11718.50\n 12289.73 11941.15\n 12437.20 12168.03\n 12586.45 12399.23\n 12737.49 12634.81\n 12890.34 12874.87\n 13045.02 13119.50\n 7 meses\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.9 [#0039]\n\n\n\n\nZana Geraldo e Otto de Mattos Oliveira são investidores e há um interesse no progresso de aplicações de cada um deles.\nEscreva um algoritmo que, a partir dos saldos atuais das duas aplicações e as respectivas taxas de juros mensais, apresente a evolução simultânea dos saldos de ambas as aplicações mês a mês (incluindo o mês inicial), até que a aplicação de Otto supere a de Zana ou até que tenham transcorridos 12 meses. O número de meses decorridos deve ser apresentado no final.\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.10 [#0042]\n\n\n\n\nExiste um grupo de voluntários para um estudo clínico, perfazendo 30 pessoas. Para cada uma delas foram coletadas diversas informações, entre elas a idade.\nEscreva um algoritmo que, a partir da sequência das 30 idades, apresente a idade máxima e a quantidade de pessoas que possuem esta idade.\n Resposta 7.14\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.11 [#0055]\n\n\n\n\n\n\nUma instituição de ensino faz o controle de desempenho dos alunos usando conceitos, como A, B, C etc. no lugar nas notas numéricas.\nPara que cálculos de médias possam ser feitos usando os conceitos, eles precisam ser convertidos para valores numéricos e o resultado convertido para conceito novamente.\nEm particular, a instituição possui a seguinte associação entre conceitos e notas:\n\n\n\n\n\nConceito\nValor numérico\n\n\n\n\nA\n10,0\n\n\nB\n8,5\n\n\nC\n6,5\n\n\nD\n5,5\n\n\nE\n3,0\n\n\nF\n0,0\n\n\n\n\n\nA conversão de nota numérica para conceito obedece à seguinte associação\n\n\n\n\n\nIntervalo\nConceito\n\n\n\n\n\\(n > 9\\)\nA\n\n\n\\(8{,}0 < n \\leq 9{,}0\\)\nB\n\n\n\\(6{,}0 < n \\leq 8{,}0\\)\nC\n\n\n\\(4{,}0 < n \\leq 6{,}0\\)\nD\n\n\n\\(0{,}0 < n \\leq 4{,}0\\)\nE\n\n\n\\(n = 0{,}0\\)\nF\n\n\n\n\n\nÉ necessário que um professor obtenha a média numérica de uma turma com 30 alunos, sendo que as informações disponíveis são os conceitos de cada um deles.\nEscreva um algoritmo para, a partir de 30 conceitos, apresentar a média numérica referente a esses conceitos.", + "text": "Problema 5.1 [#0031]\n\n\n\n\nEm uma competição de natação, as categorias são determinadas segundo a idade dos competidores.\nCategorias:\n\nInfantil A: até 4 anos;\nInfantil B: 5 e 6 anos;\nInfantil C: 7 a 10 anos;\nJuvenil A: 11 a 13 anos;\nJuvenil B: 14 a 17 anos;\nSênior: 18 ou mais anos.\n\nO número de vagas total para a competição é 200, sem separação entre as categorias. Embora tenha tenham sido preenchidas todas as vagas, houve uma preocupação grande quanto às categorias Infantil A e Sênior, temendo que não houvesse atletas suficientes para elas.\nEscreva um algoritmo completo para processar a idade de todos os participantes e determinar a quantidade de nadadores pertencentes ao Infantil A e Sênior.\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.2 [#0032]\n\n\n\n\nUm sistema monitora a pressão de uma caldeira registrando uma medida a cada cinco minutos. Como o sistema funciona continuamente, os dados são registrados diariamente, com a primeira medida a 0h e a última às 23h55min.\nEscreva um algoritmo para processar todos os dados colhido em um dia e determinar a a pressão média nesse período.\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.3 [#0033]\n\n\n\n\nÉ preciso processar o resultado de uma pesquisa de opinião para a qual era possível escolher entre sim, não e não sei.\nEscreva um algoritmo para processar uma sequência de respostas (com mínimo de uma resposta) e determinar as porcentagens de cada categoria.\nDica: Represente as comparações usando texto em nível alto de abstração (exemplo: “se a resposta foi sim, então…”).\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.4 [#0034]\n\n\n\n\nUm relatório de gastos é apresentado mensalmente ao gerente de uma empresa. Nesse relatório constam, logo no início, a quantidade de despesas individuais e, seguindo a essa informação, vêm os valores em R$ de cada gasto realizado. Deseja-se saber quantos desses valores são superiores a R$1000,00.\nEscreva um algoritmo para processar os dados descritos e apresentar a quantidade desejada e a porcentagem desta em relação ao número total de gastos realizados.\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.5 [#0035]\n\n\n\n\nA Universidade promoveu um um show de música folclórica em seu Anfiteatro principal, o qual tem capacidade para 400 pessoas. Os ingressos foram grátis e distribuídos com antecedência. Na noite do espetáculo, todos os assentos foram ocupados.\nPara colher informações sobre o público participante, foi perguntado a cada ingressante sua identidade de gênero e sua idade. Os gêneros foram anotados da seguinte forma: 1 - cisgênero; 2 - transgênero e 3 - não binário.\nOs dados de interesse para a análise incluem:\n\nas porcentagens de cada grupo em relação ao total;\nas idades médias de cada grupo.\n\nEscreva um algoritmo para processar uma sequência de informações que consiste, para cada um dos presentes no show, no número referente ao seu grupo e sua idade. O pseudocódigo deve apresentar as porcentagens indicadas e as médias que existirem.\n Comentário 7.2\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.6 [#0036]\n\n\n\n\nEscreva um algoritmo para, a partir de um valor em \\(\\mathbb{Z}^*\\), apresentar todos seus divisores e a soma destes divisores.\n Resposta 7.13\n Comentário 7.3\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.7 [#0037]\n\n\n\n\nConsidere o seguinte problema:\n\nEscreva um algoritmo para processar uma sequência indefinida e não vazia de valores inteiros (todos positivos) e determinar o valor máximo. A sequência é terminada por um valor sentinela igual a -1.\n\nPara esse problema, foi apresentado o seguinte algoritmo:\n\n\n\n\n\nEssa solução, porém, contém um erro de lógica. Identifique-o e proponha a correção.\n Comentário 7.4\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.8 [#0038]\n\n\n\n\nAdson Biardeyson da Gama e Rafaela Xiomara Corocher são investidores.\nAdson tem uma aplicação com valor atual de R$12.000,00. Essa aplicação rende 1,2% de juros ao mês.\nRafaela, por sua vez, tem uma aplicação de R$11.500,00, cujo rendimento mensal é de 1,9%.\nEscreva um algoritmo que apresente a evolução simultânea dos saldos de ambas as aplicações mês a mês (incluindo o mês inicial), até que a aplicação de Rafaela supere a de Adson. O número de meses decorridos até esta situação deve também ser apresentado.\nPara referência, o algoritmo deveria produzir um resultado como o seguinte:\n 12000.00 11500.00\n 12144.00 11718.50\n 12289.73 11941.15\n 12437.20 12168.03\n 12586.45 12399.23\n 12737.49 12634.81\n 12890.34 12874.87\n 13045.02 13119.50\n 7 meses\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.9 [#0039]\n\n\n\n\nZana Geraldo e Otto de Mattos Oliveira são investidores e há um interesse no progresso de aplicações de cada um deles.\nEscreva um algoritmo que, a partir dos saldos atuais das duas aplicações e as respectivas taxas de juros mensais, apresente a evolução simultânea dos saldos de ambas as aplicações mês a mês (incluindo o mês inicial), até que a aplicação de Otto supere a de Zana ou até que tenham transcorridos 12 meses. O número de meses decorridos deve ser apresentado no final.\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.10 [#0042]\n\n\n\n\nExiste um grupo de voluntários para um estudo clínico, perfazendo 30 pessoas. Para cada uma delas foram coletadas diversas informações, entre elas a idade.\nEscreva um algoritmo que, a partir da sequência das 30 idades, apresente a idade máxima e a quantidade de pessoas que possuem esta idade.\n Resposta 7.14\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.11 [#0055]\n\n\n\n\n\n\nUma instituição de ensino faz o controle de desempenho dos alunos usando conceitos, como A, B, C etc. no lugar nas notas numéricas.\nPara que cálculos de médias possam ser feitos usando os conceitos, eles precisam ser convertidos para valores numéricos e o resultado convertido para conceito novamente.\nEm particular, a instituição possui a seguinte associação entre conceitos e notas:\n\n\n\n\n\nConceito\nValor numérico\n\n\n\n\nA\n10,0\n\n\nB\n8,5\n\n\nC\n6,5\n\n\nD\n5,5\n\n\nE\n3,0\n\n\nF\n0,0\n\n\n\n\n\nA conversão de nota numérica para conceito obedece à seguinte associação\n\n\n\n\n\nIntervalo\nConceito\n\n\n\n\n\\(n > 9\\)\nA\n\n\n\\(8{,}0 < n \\leq 9{,}0\\)\nB\n\n\n\\(6{,}0 < n \\leq 8{,}0\\)\nC\n\n\n\\(4{,}0 < n \\leq 6{,}0\\)\nD\n\n\n\\(0{,}0 < n \\leq 4{,}0\\)\nE\n\n\n\\(n = 0{,}0\\)\nF\n\n\n\n\n\nÉ necessário que um professor obtenha a média numérica de uma turma com 30 alunos, sendo que as informações disponíveis são os conceitos de cada um deles.\nEscreva um algoritmo para, a partir de 30 conceitos, apresentar a média numérica referente a esses conceitos.\n\n\n\n\n\n\n\n\n\n\n\n\n\nProblema 5.12 [#0069]\n\n\n\n\nUm número inteiro é comummente escrito na base 10. Assim, o número \\(2601\\) pode ser entendido como \\({1 \\times 10^0} + {0 \\times 10^1} + {6 \\times 10^2} + {2 \\times 10^3}\\).\nEscreva um algoritmo que decomponha qualquer valor inteiro positivo em suas potências de 10 (começando pelas unidades; \\(10^0\\)). A solução deve deixar claros os cálculos usados para separar o valor em suas partes relevantes.\nComo exemplo, para 1003, apresentar\n3 x 10^0\n0 x 10^1\n0 x 10^2\n1 x 10^3", "crumbs": [ "Repetições", "5  Problemas variados com repetições e condicionais" @@ -154,7 +154,7 @@ "href": "pratica-algoritmos-listagem-geral.html", "title": "Apêndice A — Listagem geral de problemas", "section": "", - "text": "Listagem dos problemas por ordem de código:\n\n\n#0001: Problema 1.3\n#0002: Problema 1.1\n#0003: Problema 1.2\n#0004: Problema 4.7\n#0005: Problema 1.4\n#0006: Problema 1.5\n#0007: Problema 1.6\n#0008: Problema 1.8\n#0009: Problema 1.9\n#0010: Problema 1.7\n#0011: Problema 3.1\n#0012: Problema 3.2\n#0013: Problema 3.3\n#0014: Problema 3.4\n#0015: Problema 3.5\n#0016: Problema 3.6\n#0017: Problema 3.7\n#0018: Problema 3.8\n#0019: Problema 3.9\n#0020: Problema 3.10\n#0021: Problema 4.1\n#0022: Problema 4.2\n#0023: Problema 4.5\n#0024: Problema 4.6\n#0025: Problema 4.3\n#0026: Problema 4.9\n#0027: Problema 4.10\n#0028: Problema 4.8\n#0029: Problema 4.11\n#0030: Problema 4.4\n#0031: Problema 5.1\n#0032: Problema 5.2\n#0033: Problema 5.3\n#0034: Problema 5.4\n#0035: Problema 5.5\n#0036: Problema 5.6\n#0037: Problema 5.7\n#0038: Problema 5.8\n#0039: Problema 5.9\n#0040: Problema 6.1\n#0041: Problema 6.2\n#0042: Problema 5.10\n#0054: Problema 1.10\n#0055: Problema 5.11\n#0058: Problema B.2\n#0058: Problema B.2\n#0060: Problema B.3\n#0061: Problema B.4\n#0062: Problema B.5\n#0063: Problema B.6\n#0064: Problema B.7\n#0065: Problema B.9\n#0066: Problema B.8\n#0067: Problema B.10\n#0068: Problema 6.3", + "text": "Listagem dos problemas por ordem de código:\n\n\n#0001: Problema 1.3\n#0002: Problema 1.1\n#0003: Problema 1.2\n#0004: Problema 4.7\n#0005: Problema 1.4\n#0006: Problema 1.5\n#0007: Problema 1.6\n#0008: Problema 1.8\n#0009: Problema 1.9\n#0010: Problema 1.7\n#0011: Problema 3.1\n#0012: Problema 3.2\n#0013: Problema 3.3\n#0014: Problema 3.4\n#0015: Problema 3.5\n#0016: Problema 3.6\n#0017: Problema 3.7\n#0018: Problema 3.8\n#0019: Problema 3.9\n#0020: Problema 3.10\n#0021: Problema 4.1\n#0022: Problema 4.2\n#0023: Problema 4.5\n#0024: Problema 4.6\n#0025: Problema 4.3\n#0026: Problema 4.9\n#0027: Problema 4.10\n#0028: Problema 4.8\n#0029: Problema 4.11\n#0030: Problema 4.4\n#0031: Problema 5.1\n#0032: Problema 5.2\n#0033: Problema 5.3\n#0034: Problema 5.4\n#0035: Problema 5.5\n#0036: Problema 5.6\n#0037: Problema 5.7\n#0038: Problema 5.8\n#0039: Problema 5.9\n#0040: Problema 6.1\n#0041: Problema 6.2\n#0042: Problema 5.10\n#0054: Problema 1.10\n#0055: Problema 5.11\n#0058: Problema B.2\n#0058: Problema B.2\n#0060: Problema B.3\n#0061: Problema B.4\n#0062: Problema B.5\n#0063: Problema B.6\n#0064: Problema B.7\n#0065: Problema B.9\n#0066: Problema B.8\n#0067: Problema B.10\n#0068: Problema 6.3\n#0069: Problema 5.12", "crumbs": [ "Apêndices", "A  Listagem geral de problemas"