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Indices.md

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When solving equations like this,

(-1)^m + 2^(m-1) = 9

Take each case on m and solve them. I.e in this case the first case would be, m being positive. and the second case would be m being negative.

Case 1: m is even If m is even, we can write (-1)^m as 1, and the equation becomes: 1 + 2^(m-1) = 9

Subtracting 1 from both sides: 2^(m-1) = 8

Since 2^3 = 8, we have: m - 1 = 3

Adding 1 to both sides: m = 4

Therefore, m = 4 is a solution for the case when m is even.

Case 2: m is odd If m is odd, we can write (-1)^m as -1, and the equation becomes: -1 + 2^(m-1) = 9

Adding 1 to both sides: 2^(m-1) = 10

Since there is no power of 2 that equals 10, there are no solutions for the case when m is odd.

Therefore, the only solution to the equation (-1)^m + 2^(m-1) = 9 is m = 4.