Given inorder and postorder traversal of a tree, construct the binary tree.
Note:
You may assume that duplicates do not exist in the tree.
inorder = [9,3,15,20,7] postorder = [9,15,7,20,3]
Return the following binary tree:
3 / \ 9 20 / \ 15 7
Given inorder and postorder traversal of a tree, construct the binary tree.
Note:
You may assume that duplicates do not exist in the tree.
inorder = [9,3,15,20,7] postorder = [9,15,7,20,3]
Return the following binary tree:
3 / \ 9 20 / \ 15 7