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answer.java
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answer.java
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class Trie {
// Node inner class
class Node {
public char val;
public boolean word;
public Node[] children = new Node[26];
public Node() {
this.val = ' ';
this.word = false;
}
// Constructor to add char
Node(char c){
Node node = new Node();
node.val = c;
}
}
private Node root;
/** Initialize your data structure here. */
public Trie() {
root = new Node();
}
/** Inserts a word into the trie. */
public void insert(String word) {
Node node = root;
// Loop through word
for (int i = 0; i < word.length(); i++) {
char c = word.charAt(i);
// If null, create new node
// Ascii arithmetic will produce correct index
if(node.children[c - 'a'] == null){
node.children[c - 'a'] = new Node(c);
}
node = node.children[c - 'a'];
}
// Mark it's a word
node.word = true;
}
/** Returns if the word is in the trie. */
public boolean search(String word) {
Node node = root;
for (int i = 0; i < word.length(); i++) {
char c = word.charAt(i);
if (node.children[c - 'a'] == null) return false;
node = node.children[c - 'a'];
}
// Takes care of case where word may be a substring but not a word itself
return node.word;
}
/** Returns if there is any word in the trie that starts with the given prefix. */
public boolean startsWith(String prefix) {
Node node = root;
for (int i = 0; i < prefix.length(); i++) {
char c = prefix.charAt(i);
if (node.children[c - 'a'] == null) return false;
node = node.children[c - 'a'];
}
return true;
// INCORRECT CASE - PREFIX IS A PREFIX OF ITSELF
// Loop through the remaining node to see if there are any words
/*for (int i = 0; i < root.children.length; i++) {
if (root.children[i] != null) return true;
}
return false;
*/
}
}
/**
* Your Trie object will be instantiated and called as such:
* Trie obj = new Trie();
* obj.insert(word);
* boolean param_2 = obj.search(word);
* boolean param_3 = obj.startsWith(prefix);
*/