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Documentation for E03

Goal

The goal of this assignment was to calculate subnets as well as supernets and get to know Internet registers.

Student number from Peppi

2112415
vvxyzki

Use your own student number and form the following subnets: 10.xy.yz.0/24 and 192.168.ki.0/24

 10.12.24.0/24 and 192.168.15.0/24

Exercise 1

What is the usable (host) address range of 192.168.15.0/24? What is the broadcast address? What is the subnet address?

Solution logic

1111 1111. 1111 1111. 1111 1111. 0000 0000.
ssss ssss. ssss ssss. ssss ssss. hhhh hhhh.

hhhh hhhh. BIN(0-1)   |   DEC
0000 0000             |   .0
0000 0001             |   .1 -first usable 
0000 0010             |   .2
0000 0011             |   .3
0000 0100             |   .4
0000 0101             |   .5
....
1111 1110             |  .254 -last usable 
1111 1111             |  .255 -broadcast address 


/24 is a subnet mask 


Answer: 192.168.15.1 - 192.168.15.254

Exercise 2

Divide the 192.168.15.0/24 into smaller subnets with (atleast) 50 hosts in each. Notice! Make as small of a subnet/subnets as you can!

Solution logic

h= host bits 
2^h formula for calculating subnets
2^8=256-2(subnet and broadcast)=254 usable adresses
2^7=128 host adresses
2^6=64 adresses <-the smallest we can do
2^5=32 adresses 

By default there are 254 hosts 

    255.       255.       255.      192   (DEC)    
1111 1111. 1111 1111. 1111 1111. 1100 0000. (BINARY)
ssss ssss. ssss ssss. ssss ssss. sshh hhhh.

we get /26 subnet bits 
255.255.255.192 - subnet mask 


192.168.15.0/26

hh hhhh
00 0000     |subnet address
00 0001     |first usable adress 
00 0010     
00 0100
...
11 1100     |.60
11 1101     |.61
11 1110     |.62 last usable adress
11 1111     |.63 broadcast        


Answers:
* Broadcast address: 192.168.15.63
* What is the subnet address: 192.168.15.0
* Usable host range 192.168.15.1-192.168.15.62
Specification Subnet info
Network address 192.168.15.0/26
New subnet mask 255.255.255.192
Number of usable hosts in the subnet 62
First IP Host address 192.168.15.1
Last IP Host address 192.168.15.62
Broadcast address 192.168.15.63

Exercise 3

Divide the 10.12.24.0/24 into smaller subnets: The subnets have to be as small as possible (usable hosts) The subnets must have the capability to support 13 hosts in each of the subnets

Solution logic

2^7=128 addresses
2^6=64 addresses
2^5=32 addresses
2^4=16         <-the best one
2^3=8

h = 4
s = 24 + 4 = 28


    255.       255.       255.      240.
1111 1111. 1111 1111. 1111 1111. 0000 0000.  
ssss ssss. ssss ssss. ssss ssss. hhhh hhhh.

First subnet

ssss|hhhh
0000 0000   .0
0000 0001   .1
...
0000 1110   .14
0000 1111   .15
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.0/28
First IP Host address 10.12.24.1
Last IP Host address 10.12.24.14
Broadcast address 10.12.24.15

Second subnet

ssss|hhhh
0001 0000   .16
0001 0001   .17
...
0001 1110   .30
0001 1111   .31
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.16/28
First IP Host address 10.12.24.17
Last IP Host address 10.12.24.30
Broadcast address 10.12.24.31

Third subnet

ssss|hhhh
0010 0000   .32
0010 0001   .33
...
0010 1110   .46
0010 1111   .47
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.32/28
First IP Host address 10.12.24.33
Last IP Host address 10.12.24.46
Broadcast address 10.12.24.47

Fourth subnet

ssss|hhhh
0011 0000   .48
0011 0001   .49
...
0011 1110   .62
0011 1111   .63
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.48/28
First IP Host address 10.12.24.49
Last IP Host address 10.12.24.62
Broadcast address 10.12.24.63

Fifth subnet

ssss|hhhh
0100 0000   .64
0100 0001   .65
...
0100 1110   .78
0100 1111   .79
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.64/28
First IP Host address 10.12.24.65
Last IP Host address 10.12.24.78
Broadcast address 10.12.24.79

Sixth subnet

ssss|hhhh
0101 0000   .80
0101 0001   .81
...
0101 1110   .94
0101 1111   .95
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.80/28
First IP Host address 10.12.24.81
Last IP Host address 10.12.24.94
Broadcast address 10.12.24.95

Seventh subnet

ssss|hhhh
0110 0000   .96
0110 0001   .97
...
0110 1110   .110
0110 1111   .111
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.96/28
First IP Host address 10.12.24.97
Last IP Host address 10.12.24.110
Broadcast address 10.12.24.111

Eighth subnet

ssss|hhhh
0111 0000   .112
0111 0001   .113
...
0111 1110   .126
0111 1111   .127
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.112/28
First IP Host address 10.12.24.113
Last IP Host address 10.12.24.126
Broadcast address 10.12.24.127

Ninth subnet

ssss|hhhh
1000 0000   .128
1000 0001   .129
...
1000 1110   .142
1000 1111   .143
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.128/28
First IP Host address 10.12.24.129
Last IP Host address 10.12.24.142
Broadcast address 10.12.24.143

Tenth subnet

ssss|hhhh
1001 0000   .144
1001 0001   .145
...
1001 1110   .158
1001 1111   .159
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.144/28
First IP Host address 10.12.24.145
Last IP Host address 10.12.24.158
Broadcast address 10.12.24.159

Eleventh subnet

ssss|hhhh
1010 0000   .160
1010 0001   .161
...
1010 1110   .174
1010 1111   .175
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.160/28
First IP Host address 10.12.24.161
Last IP Host address 10.12.24.174
Broadcast address 10.12.24.175

Twelfth subnet

ssss|hhhh
1011 0000   .176
1011 0001   .177
...
1011 1110   .190
1011 1111   .191
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.176/28
First IP Host address 10.12.24.177
Last IP Host address 10.12.24.190
Broadcast address 10.12.24.191

Thirteenth subnet

ssss|hhhh
1100 0000   .192
1100 0001   .193
...
1100 1110   .206
1100 1111   .207
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.192/28
First IP Host address 10.12.24.193
Last IP Host address 10.12.24.206
Broadcast address 10.12.24.207

Fourteenth subnet

ssss|hhhh
1101 0000   .208
1101 0001   .209
...
1101 1110   .222
1101 1111   .223
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.208/28
First IP Host address 10.12.24.209
Last IP Host address 10.12.24.222
Broadcast address 10.12.24.223

Fifteenth subnet

ssss|hhhh
1110 0000   .224
1110 0001   .225
...
1110 1110   .238
1110 1111   .239
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.224/28
First IP Host address 10.12.24.225
Last IP Host address 10.12.24.238
Broadcast address 10.12.24.239

Sixteenth subnet

ssss|hhhh
1110 0000   .240
1110 0001   .241
...
1110 1110   .254
1110 1111   .255
Specification Subnet info
New subnet mask 255.255.255.240
Number of usable hosts in the subnet 13
Network address 10.12.24.240/28
First IP Host address 10.12.24.241
Last IP Host address 10.12.24.254
Broadcast address 10.12.24.255

Exercise 4

Divide the last subnet, of from exercise 3, into smaller subnets: The subnets have to be as small as possible (usable hosts) The subnets must have the capability to support 2 hosts in each of the subnets The subnets have to be as small as possible (usable hosts)

Subnet mask Network address First host address Last host address Broadcast address Usable addresses
255.255.255.252 10.12.24.240/30 10.12.24.241 10.12.24.242 10.12.24.243 2
255.255.255.252 10.12.24.244/30 10.12.24.245 10.12.24.246 10.12.24.247 2

Exercise 5

Is subnet 10.12.24.0/24 a part of the supernet 10.12.16.0/20?

Solution logic



Subnet 10.12.24.0/24

Specification Subnet info
Subnet mask 255.255.255.0
Number of usable hosts in the subnet 254
Network address 10.12.24.0/24
First IP Host address 10.12.24.1
Last IP Host address 10.12.24.254
Broadcast address 10.12.24.255

Supernet 10.12.16.0/20

Specification Supernet info
Subnet mask 255.255.240.0
Number of usable hosts in the subnet 4094
Network address 10.12.16.0/20
First IP Host address 10.12.16.1
Last IP Host address 10.12.31.254
Broadcast address 10.12.31.255



Lets subnet supernet 10.12.16.0/20 to the size of /24. We got 2^4=16 subnet adresses in range of 10.12.16.0/24 - 10.12.31.0/24. It includes subnet 10.12.24.0/24

Exercise 6

Is subnet 10.12.24.0/24 a part of supernet 10.0.0.0/8?

Subnet 10.12.24.0/24

Specification Subnet info
Subnet mask 255.255.255.0
Number of usable hosts in the subnet 254
Network address 10.12.24.0
First IP Host address 10.12.24.1
Last IP Host address 10.12.24.254
Broadcast address 10.12.24.255

Supernet 10.0.0.0/8

Specification Supernet info
Subnet mask 255.0.0.0
Number of usable hosts in the subnet 16777214
Network address 10.0.0.0
First IP Host address 10.0.0.1
Last IP Host address 10.255.255.254
Broadcast address 10.255.255.255



Lets subnet supernet 10.0.0.0/8 to the size of /24. We got 2^16=65534 subnet adresses in range of 10.0.0.0/24 - 10.255.255.0/24. It includes subnet 10.12.24.0/24


Investigation of the IP with ripe.net

Internet registries

Fill the following addresses with your student number: 195.12.24.0/24, 43.12.15.0/24, 15.15.12.0/24 and 100.24.15.0/24. Search to whom they are registered to

195.12.24.0/24 
This ip is registered to RIPE NNC

43.12.15.0/24
This ip is registered to APNIC

15.15.12.0/24
This ip is registered to ARIN

100.24.15.0/24
This ip is registered to ARIN