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011_container_with_most_water.cpp
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011_container_with_most_water.cpp
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/*
Container With Most Water
URL: https://leetcode.com/problems/container-with-most-water
Tags: ['array', 'two-pointers']
___
Given n non-negative integers a 1, a 2, ..., a n , where each represents a
point at coordinate ( i , a i). n vertical lines are drawn such that the two
endpoints of line i is at ( i , a i) and ( i , 0). Find two lines, which
together with x-axis forms a container, such that the container contains the
most water.
Note: You may not slant the container and n is at least 2.
![](https://s3-lc-upload.s3.amazonaws.com/uploads/2018/07/17/question_11.jpg)
The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this
case, the max area of water (blue section) the container can contain is 49.
Example:
Input: [1,8,6,2,5,4,8,3,7]
Output: 49
*/
#include "test.h"
using std::vector;
namespace container_with_most_water {
inline namespace v1 {
// 思路: 从最两边开始, 向中间逼近.
// 要想找到下个比当前大的结果, 就要找到比当前最矮边更高的一边.
class Solution {
public:
int maxArea(vector<int>& height) {
int max = 0, left = 0, right = height.size() - 1;
while (left < right) {
int w = right - left, h;
if (height[left] < height[right]) {
h = height[left];
left++;
} else {
h = height[right];
right--;
}
int area = w * h;
if (area > max) {
max = area;
}
}
return max;
}
};
} // namespace v1
TEST_CASE("Container With Most Water") {
TEST_SOLUTION(maxArea, v1) {
vector<int> v = {1, 8, 6, 2, 5, 4, 8, 3, 7};
CHECK(maxArea(v) == 49);
BENCHMARK("") { return maxArea(v); };
};
}
} // namespace container_with_most_water