Solution #3733
Solution #3733
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Great job on implementing the convertToObject function! 🎉 Your code meets the task requirements and constraints effectively. While there are a few suggestions for improvement, such as handling duplicate keys and entries without colons, these do not impact the core functionality of your solution. Keep up the good work and consider these enhancements for future projects to make your code even more robust! 😊
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| @@ -6,7 +6,24 @@ | |||
| * @return {object} | |||
| */ | |||
| function convertToObject(sourceString) { | |||
| // write your code here | |||
| const entries = sourceString | |||
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The variable entries is correctly initialized by splitting the sourceString using semicolons. Ensure that sourceString is always a valid string to avoid runtime errors.
| const entries = sourceString | ||
| .split(';') | ||
| .map((entry) => entry.trim()) | ||
| .filter((entry) => entry); |
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The filter function removes empty entries, which is a good practice to avoid processing unnecessary data.
| const result = {}; | ||
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| for (const entry of entries) { | ||
| if (entry.includes(':')) { |
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Consider adding an else block to handle entries that do not contain a colon. This will ensure that all parts of the input string are processed correctly.
| const key = rawKey.trim(); | ||
| const value = rawValueParts.join(':').trim(); | ||
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| result[key] = value; |
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Currently, if there are duplicate keys in the sourceString, the last value will overwrite any previous ones. If this is not the desired behavior, consider implementing logic to handle duplicate keys.
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