solution #3788
solution #3788
Conversation
There was a problem hiding this comment.
Great job on implementing the convertToObject function! 🎉 Your code meets the task requirements and effectively converts a CSS style string into an object. You've used split, map, and filter methods well, and your variable names are mostly descriptive.
While there are a few minor suggestions for improvement, such as ensuring both key and value are defined before processing, and considering a more readable variable name like splitString, these do not impact the core functionality of your solution. Keep up the good work and continue refining your coding skills! 😊
✨ Please rate this review in the Platform's notification center. I will be grateful for your feedback! ✨
| @@ -6,7 +6,57 @@ | |||
| * @return {object} | |||
| */ | |||
| function convertToObject(sourceString) { | |||
| // write your code here | |||
| const splittedString = sourceString | |||
There was a problem hiding this comment.
The variable name splittedString is not ideal. Consider renaming it to splitString for better readability.
| const convertedToObject = {}; | ||
|
|
||
| splittedString.forEach((str) => { | ||
| const styleArr = str.split(':'); |
There was a problem hiding this comment.
The split(':') method will not handle cases where there are multiple colons within a style value. Although handling multiple colons is not required, be aware that this could lead to unexpected behavior if such cases are encountered.
| const styleArr = str.split(':'); | ||
| const [key, value] = styleArr; | ||
|
|
||
| convertedToObject[key.trim()] = value.trim(); |
There was a problem hiding this comment.
Ensure that both key and value are defined before attempting to trim and assign them to the convertedToObject. If styleArr does not contain exactly two elements, this could lead to undefined behavior.
No description provided.