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162_find_peak_element.java
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162_find_peak_element.java
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class Solution {
public int findPeakElement(int[] nums) {
if (nums.length == 1) {
return 0;
}
if (nums.length == 2) {
return nums[0] > nums[1]? 0: 1;
}
int length = nums.length;
float[] arr = new float[length+2];
arr[0] = Float.NEGATIVE_INFINITY;
for (int i = 0; i < length; i++) {
arr[i+1] = nums[i];
}
arr[length+1] = Float.NEGATIVE_INFINITY;
int ans = binarySearchPeak(arr, 1, length) - 1;
return ans;
}
public int binarySearchPeak(float[] arr, int left, int right) {
if (left > right) {
return 0;
}
if (left == right) {
return left;
}
int mid = left + (right - left) / 2;
int ans = 0;
if (arr[mid] > arr[mid-1] && arr[mid] > arr[mid+1]) {
ans = mid;
}
int leftAns = binarySearchPeak(arr, left, mid-1);
int rightAns = binarySearchPeak(arr, mid+1, right);
if (arr[ans] < arr[leftAns]) {
ans = leftAns;
} if (arr[ans] < arr[rightAns]) {
ans = rightAns;
}
return ans;
}
}
/**
* This is my personal record of solving Leetcode Problems.
* If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
* Copyright (C) 2020-2022 mengxinayan
*
* This program is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with this program. If not, see <http://www.gnu.org/licenses/>.
*/