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Copy path621_task_scheduler.java
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621_task_scheduler.java
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class Solution {
public int leastInterval(char[] tasks, int n) {
Map<Character, Integer> map = new HashMap<>();
for (int i = 0; i < tasks.length; i++) {
if (map.containsKey(tasks[i]) == false) {
map.put(tasks[i], 1);
} else {
map.put(tasks[i], map.get(tasks[i])+1);
}
}
PriorityQueue<CharCount> pq = new PriorityQueue<>();
for (Character ch : map.keySet()) {
pq.offer(new CharCount(ch, map.get(ch)));
}
int ans = 0;
int taskNumber = tasks.length;
List<CharCount> charCountArr = new ArrayList<>();
while (taskNumber != 0) {
charCountArr.clear();
for (int i = 0; i <= n; i++) {
if (pq.size() > 0) {
CharCount tmp = pq.poll();
tmp.count--;
if (tmp.count != 0) {
charCountArr.add(tmp);
}
taskNumber--;
ans++;
} else {
if (charCountArr.isEmpty()) {
break;
} else {
ans++;
}
}
}
for (CharCount tmp : charCountArr) {
pq.offer(tmp);
}
}
return ans;
}
}
class CharCount implements Comparable<CharCount> {
public char ch;
public int count;
public CharCount(char ch, int count) {
this.ch = ch;
this.count = count;
}
@Override
public int compareTo(CharCount o) {
if (count == o.count) {
return ch - o.ch;
} else {
// From big to small
return o.count - count;
}
}
}
/**
* This is my personal record of solving Leetcode Problems.
* If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
* Copyright (C) 2020-2022 mengxinayan
*
* This program is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with this program. If not, see <http://www.gnu.org/licenses/>.
*/