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15_3sum.py
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15_3sum.py
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class Solution:
def threeSum(self, nums: List[int]) -> List[List[int]]:
if len(nums) < 3:
return []
nums.sort()
ans = []
for i in range(len(nums)-2):
# Some details
if (i >= 1) and (nums[i] == nums[i-1]):
continue
if nums[i] > 0:
break
left = i+1
right = len(nums) - 1
while left < right:
tmp_sum = nums[i] + nums[left] + nums[right]
if tmp_sum < 0:
left += 1
elif tmp_sum > 0:
right -= 1
else:
ans.append([nums[i], nums[left], nums[right]])
while (left < right) and (nums[left+1] == nums[left]):
left += 1
while (left < right) and (nums[right-1] == nums[right]):
right -= 1
left += 1
right -= 1
return ans
'''
This is my personal record of solving Leetcode Problems.
If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
Copyright (C) 2020-2022 mengxinayan
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
'''