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17_letter_combinations_of_a_phone_number.py
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17_letter_combinations_of_a_phone_number.py
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# Solution 1: Generate
class Solution:
def letterCombinations(self, digits: str) -> List[str]:
num_ch_dict = {'2': ['a', 'b', 'c'], '3': ['d', 'e', 'f'], \
'4': ['g', 'h', 'i'], '5': ['j', 'k', 'l'], '6': ['m', 'n', 'o'], \
'7': ['p', 'q', 'r', 's'], '8': ['t', 'u', 'v'], '9': ['w', 'x', 'y', 'z']}
if digits == '':
return []
ans = ['']
for ch in digits:
ans = [pre + curr for pre in ans for curr in num_ch_dict[ch]]
return ans
# Solution 2: Backtracing
class Solution:
def letterCombinations(self, digits: str) -> List[str]:
def backtracking(tmp: str, index: int):
if index == len(digits):
ans.append(tmp)
else:
for ch in num_ch_dict[digits[index]]:
tmp += ch
backtracking(tmp, index+1)
tmp = tmp[:len(tmp)-1]
num_ch_dict = {'2': ['a', 'b', 'c'], '3': ['d', 'e', 'f'], \
'4': ['g', 'h', 'i'], '5': ['j', 'k', 'l'], '6': ['m', 'n', 'o'], \
'7': ['p', 'q', 'r', 's'], '8': ['t', 'u', 'v'], '9': ['w', 'x', 'y', 'z']}
if digits == '':
return []
ans = []
backtracking('', 0)
return ans
'''
This is my personal record of solving Leetcode Problems.
If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
Copyright (C) 2020-2022 mengxinayan
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
'''