405_convert_a_number_to_hexadecimal.py

class Solution:
    def toHex(self, num: int) -> str:
        if num == 0:
            return '0'
        ans = ''
        number = '0123456789abcdef'
        mask = 0xf
        for i in range(8):
            ans = number[num & mask] + ans
            num = num >> 4
        ans = ans.lstrip('0')
        return ans

'''
    This is my personal record of solving Leetcode Problems. 
    If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
    Copyright (C) 2020-2022  mengxinayan

    This program is free software: you can redistribute it and/or modify
    it under the terms of the GNU General Public License as published by
    the Free Software Foundation, either version 3 of the License, or
    (at your option) any later version.

    This program is distributed in the hope that it will be useful,
    but WITHOUT ANY WARRANTY; without even the implied warranty of
    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
    GNU General Public License for more details.

    You should have received a copy of the GNU General Public License
    along with this program.  If not, see <http://www.gnu.org/licenses/>.
'''