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49_group_anagrams.py
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# Solution 1: sorted string
class Solution:
def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
strs_sorted = []
for string in strs:
strs_sorted.append(''.join(sorted(string)))
string_dict = {}
for i in range(len(strs)):
if strs_sorted[i] not in string_dict:
string_dict[strs_sorted[i]] = [strs[i]]
else:
string_dict[strs_sorted[i]].append(strs[i])
ans = []
for value in string_dict.values():
ans.append(value)
return ans
# Solution 2: count number
class Solution:
def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
def count_str(string: str) -> tuple:
ans = [0 for i in range(26)]
for ch in string:
ans[ord(ch) - ord('a')] += 1
return tuple(ans)
count_str_dict = {}
for string in strs:
tmp_tuple = count_str(string)
if tmp_tuple not in count_str_dict:
count_str_dict[tmp_tuple] = [string]
else:
count_str_dict[tmp_tuple].append(string)
ans = []
for value in count_str_dict.values():
ans.append(value)
return ans
'''
This is my personal record of solving Leetcode Problems.
If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
Copyright (C) 2020-2022 mengxinayan
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
'''