606_construct_string_from_binary_tree.py

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution:
    def tree2str(self, t: TreeNode) -> str:
        if t == None:
            return ''
        elif (t != None) and (t.left == None) and (t.right == None):
            return str(t.val)
        elif (t != None) and (t.left != None) and (t.right == None):
            return str(t.val) + '(' + self.tree2str(t.left) + ')'
        elif (t != None) and (t.left == None) and (t.right != None):
            return str(t.val) + '()' + '(' + self.tree2str(t.right) + ')'
        else:
            return str(t.val) + '(' + self.tree2str(t.left) + ')' + '(' + self.tree2str(t.right) + ')'

'''
    This is my personal record of solving Leetcode Problems. 
    If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
    Copyright (C) 2020-2022  mengxinayan

    This program is free software: you can redistribute it and/or modify
    it under the terms of the GNU General Public License as published by
    the Free Software Foundation, either version 3 of the License, or
    (at your option) any later version.

    This program is distributed in the hope that it will be useful,
    but WITHOUT ANY WARRANTY; without even the implied warranty of
    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
    GNU General Public License for more details.

    You should have received a copy of the GNU General Public License
    along with this program.  If not, see <http://www.gnu.org/licenses/>.
'''