985_sum_of_even_numbers_after_queries.py

class Solution:
    def sumEvenAfterQueries(self, A: List[int], queries: List[List[int]]) -> List[int]:
        even_sum = 0
        ans = []
        for num in A:
            if num % 2 == 0:
                even_sum += num
        for query in queries:
            if A[query[1]] % 2 == 0:
                even_sum -= A[query[1]]
            A[query[1]] += query[0]
            if A[query[1]] % 2 == 0:
                even_sum += A[query[1]]
            ans.append(even_sum)
        return ans

'''
    This is my personal record of solving Leetcode Problems. 
    If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
    Copyright (C) 2020-2022  mengxinayan

    This program is free software: you can redistribute it and/or modify
    it under the terms of the GNU General Public License as published by
    the Free Software Foundation, either version 3 of the License, or
    (at your option) any later version.

    This program is distributed in the hope that it will be useful,
    but WITHOUT ANY WARRANTY; without even the implied warranty of
    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
    GNU General Public License for more details.

    You should have received a copy of the GNU General Public License
    along with this program.  If not, see <http://www.gnu.org/licenses/>.
'''