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Copy path993_cousins_in_binary_tree.py
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993_cousins_in_binary_tree.py
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# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isCousins(self, root: TreeNode, x: int, y: int) -> bool:
def dfs(node: TreeNode, parent: int):
if node != None:
if parent != None:
self.depth_dict[node.val] = 1 + self.depth_dict[parent.val]
else:
self.depth_dict[node.val] = 0
self.parent_dict[node.val] = parent
dfs(node.left, node)
dfs(node.right, node)
self.depth_dict = {}
self.parent_dict = {}
dfs(root, None)
return (self.depth_dict[x] == self.depth_dict[y]) and (self.parent_dict[x] != self.parent_dict[y])
'''
This is my personal record of solving Leetcode Problems.
If you have any questions, please discuss them in [Issues](https://github.com/mengxinayan/leetcode/issues).
Copyright (C) 2020-2022 mengxinayan
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
'''