038-PandigitalMultiples.py

#!/usr/bin/python3
# -*- coding: utf-8 -*-
# Take the number 192 and multiply it by each of 1, 2, and 3:
#    192 × 1 = 192
#    192 × 2 = 384
#    192 × 3 = 576
# By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)
# The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).
# What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , n) where n > 1?

from functions import ispandigital

largest = 1
for p in range(1,10000):
    n=''
    q=1
    while(len(n)<9):
        n=n+''.join(str(p*q))
        q += 1
    if(len(n)==9 and ispandigital(int(n))==1):
        largest=max(largest,int(n))
print(largest)