The macro name is the same as the std member

[XY-ShadowK]

Describe the bug

#if !defined(isfinite)
#include <float.h>
#define isfinite _finite
#endif

The macro name isfinite is the same as std::isfinite, which can cause compiler to incorrectly replace std::isfinite to std::_finite.

To Reproduce
Just use std::isfinite after the inclusion of jsoncpp.cpp.

Expected behavior
A clear and concise description of what you expected to happen.

Desktop (please complete the following information):

• OS: Windows 10 22H2 x64

Additional context
Please use std::isfinite to check values, or use _isfinite directly or use other macro name to circumvent std member names.