Write a function:
function solution(A);
that, given a non-empty zero-indexed array A of N integers, returns the minimal positive integer (greater than 0) that does not occur in A.
For example, given:
A[0] = 1
A[1] = 3
A[2] = 6
A[3] = 4
A[4] = 1
A[5] = 2
the function should return 5.
Assume that:
N is an integer within the range [1..100,000]; each element of array A is an integer within the range [−2,147,483,648..2,147,483,647]. Complexity:
expected worst-case time complexity is O(N); expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments). Elements of input arrays can be modified.
// you can write to stdout for debugging purposes, e.g.
// console.log('this is a debug message');
function solution(A) {
// Filter positive
A = A.filter(i => (i > 0))
// sort arrays
A.sort((a, b) => (a - b))
if (A.length == 1 && A[0] === 1) {
return 2
}
if (A[0] !== 1) return 1
for (var i=1; i<A.length; i++) {
if ((A[i] - A[i-1]) > 1) return A[i-1] + 1
}
return A[A.lenth -1] + 1
}