Final alignment fix.

index.md

@@ -378,9 +378,9 @@ expanded form with all the terms lined up:
 
 $$
   \begin{align*}
-    \ln(1+x) &= & &x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} \
+    \ln(1+x) &= +x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} \
                + \frac{x^5}{5} - \frac{x^6}{6} + \ldots     \\
-    \ln(1-x) &= &- &x - \frac{x^2}{2} - \frac{x^3}{3} - \frac{x^4}{4} \
+    \ln(1-x) &= -x - \frac{x^2}{2} - \frac{x^3}{3} - \frac{x^4}{4} \
                - \frac{x^5}{5} - \frac{x^6}{6} - \ldots
   \end{align*}
 $$